Answer:
x₂=2×1
Explanation:
According to the work-energy theorem, we can assume that the gravitational potential energy at the lowest point of compression is zero since the kinetic energy change is 0;
mgx-(kx)²/2 =0 where m refers to the object's mass, g indicates the acceleration due to gravity, k denotes spring constant, and x represents the spring's compression.
mgx=(kx)²/2
x=2mg/k----------------compression when the object is at rest
However, ΔK.E =-1/2mv²⇒kx²=mv² -----------where v symbolizes the object's velocity and K.E signifies kinetic energy
Thus, if kx²=mv² then
v=x *√(k/m) ----------------where v=0
<pDoubling v results in multiplying x *√(k/m) by 2, leading to x₂ being double x₁
Answer:
Explanation:
Provided:
mass of the steel ball 
initial velocity of the ball 
Final velocity of the ball
(moving upwards)
The impulse given is determined by the change in the momentum of the object.
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Thus, the magnitude of the Impulse is 4 N-s.
</ptherefore>
Transverse waves propagate in a direction that is at right angles to the movement of the particles (or the medium involved). Hence, the particles would be shifting from east to west, which is perpendicular to the north-south direction of the wave.
1. Initially removing a strip leaves some electrons behind, resulting in the strip becoming positively charged. 2. The roll itself does not acquire a negative charge since it is grounded by the hand holding it, causing excess negatives to repel through the hand. 3. Tearing off another strip again leaves electrons behind, this new strip is also positively charged and will repel the first strip. 4. When two strips are then pulled apart, one will transfer electrons to the other, creating one positively charged strip and one negatively charged strip, which will attract each other.
Answer:
The wire's resistivity is:

Explanation:
Remember the equation that relates resistance R to the resistivity of the material
:

where A denotes the wire's cross-sectional area, and L signifies its length.
For our case, the area for a wire with 0.33 mm diameter, is the circular area of a 0.165 mm radius (0.000165 m), calculated as:

Without the actual resistance, but knowing the current when a voltage is applied, we can apply Ohm's Law to find wire resistance R:

Now, substituting into the resistance equation provided earlier, we derive the resistivity
:
