Water waves in a small tank are .06 m long. They pass a given point at a rate of 14.8 waves every three seconds. What is the spe

Answer:

The correct option is 80 dB.

Explanation:

The transformation of sound intensity level into sound intensity utilizes the formula

[D] = 10 log (I/I₀)

Where I₀ = 10⁻¹² W/m²

[D] results in 100 dB

100 = 10 log (I/I₀)

Log (I/I₀) converts to 10

(I/I₀) = 10¹⁰

I is determined as I₀ × 10¹⁰ = 10⁻¹² × 10¹⁰ = 10⁻² W/m²

Sound intensity inversely relates to the square of the distance from the source.

I ∝ (1/d²)

I can be expressed as k/d²

When d = 1 m, the intensity is 10⁻² W/m²

Thus, 0.01 = k/1

Providing that k = 0.01 W

For d = 20 m, we can calculate I

I = 0.01/20² = 2.5 × 10⁻⁵ W/m²

With four neighbors mowing their lawns concurrently,

I = 4 × 2.5 × 10⁻⁵ = 10⁻⁴ W/m⁻²

The sound intensity level in decibels is represented as

[D] = 10 log (I/I₀)

[D] = 10 log (10⁻⁴/10⁻¹²)

[D] = 10 log (10⁸)

[D] = 10 × 8 = 80dB

A basketball player maintains a steady pace of 2.5 m/s while throwing a basketball vertically at 6.0 m/s. How far does the player advance before getting the ball back? Air resistance is negligible. I was unsure which formula to apply to this scenario. Is there any relevance to an angle? First, we determine the duration to reach peak height. The total time for the flight will be double the ascent duration. According to Newton's equations of motion: v = u + at. At the highest point, v = 0, where u is 6 m/s. Thus, the equation becomes 0 = 6 - 9.81t, leading us to t = 0.61 seconds. Therefore, the total flight time equals 1.22 seconds as the player runs towards the ball at a horizontal speed of 2.5 m/s. The distance traveled can be calculated using distance = speed × time, resulting in distance = 2.5 m/s * 1.22, yielding a final distance of 6.11m.

Answer:

v = [√(g/2h)]L

Explanation:

Let v represent the initial horizontal speed, and t denote the duration James Bond takes to leap off the ledge of length, L.

Thus, we derive vt = L, which leads to t = L/v

Additionally, considering that Bond begins with no horizontal velocity, he descends freely over the height, h; thus the equation y - y' = ut - 1/2gt² is applicable, where y = 0 (top of the cliff) and y' = -h, u = 0 (initial vertical speed), g = acceleration due to gravity = 9.8 m/s², and t = the time required to leap from the cliff = L/v.

By substituting these parameters into the equation, we obtain

y' - y = ut - 1/2gt²

-h - 0 = 0 × t - 1/2g(L/v)²

-h  = - 1/2gL²/v²

v² = gL²/2h

taking the square root of both sides gives us

v = [√(g/2h)]L

Therefore, James Bond's required minimum horizontal velocity is v = [√(g/2h)]L

We will express each number differently:
(4.48E-8) = 0.0000000448
(5.2E-4) = 0.00052
Upon performing the multiplication, the exponent will align to 10 ^ -11
Consequently, the multiplication yields:
(4.48E-8) * (5.2E-4) = 2.3296E-11
Rewriting gives us:
(4.48E-8) * (5.2E-4) = 2.33E-11
Response:
2.33E-11

145.43 N