Put the following elements into five pairs of elements that have similar chemical reactivity: F, Sr, P, Ca, O, Br, Rb, Sb, Li, S

Answer:

Step 1:

N

H

+

3

C

H

2

C

H

2

N

H

+

3

(

a

q

)

⇌

A.

K

a

1

B.

K

a

2

C.

K

b

1

D.

K

b

2

Step 2:

N

H

2

C

H

2

C

H

2

N

H

+

3

(

a

q

)

⇌

A.

K

a

1

B.

K

a

2

C.

K

b

1

D.

K

b

2

Acid-

Answer:

The correct choice is: option A.

Justification:

To address this inquiry, we need to evaluate the total number of electrons each orbital can accommodate.

  Orbital                         Number of electrons

   s                                   2

   p                                  6

   d                                 10

   f                                  14

Provided options:

A. 1s² 2s² 2p⁶ 3s²                 This configuration is valid as it aligns with the permitted number of electrons in each orbital and follows the correct sequence.

B. 1s² 2s² 2p⁶ 3s² 3d⁴          This configuration is not accurate because

                                         3d⁴ should follow 3p.

C. 1s² 2s² 2d¹⁰ 2p³                This is incorrect since 2d¹⁰ is not a valid orbital.

D. 1s² 2s^s 2p³ 2d¹⁰            This option contains two errors; s as an exponent does not exist, and 2d¹⁰ is also an invalid description.

Answer:

Explanation:

0.3(125)+0.7(126)=37.5+88.2=125.7

2. The most prevalent isotope is 32, since the average is very close to this value.