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Alina
14 days ago
6

Dana and Cathy are playing tennis. The probability that Dana wins at least one out of two games is 0.3. What is the probability

that Dana wins at least one out of four
Mathematics
1 answer:
Inessa [12.5K]14 days ago
3 0

Answer:

51%.

Step-by-step explanation:

Given that the probability of at least one win is 0.3, it indicates that the chance of none winning is:

1 - 0.3 = 0.7 represents the probability of losing in the first two games. Since these are independent events, the chance of not winning in all four games is:

(0.7) * (0.7) = 0.49

Consequently, the likelihood of winning at least one game equals the complement of not winning any, hence:

1 - 0.49 = 0.51

This implies a 51% probability of winning at least one out of four games.

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PIT_PIT [12445]
We are given the points
<span>E (0, 27)
</span><span>F (5,−8)

and we need to calculate the rate of change and the initial value:

To determine the rate of change, we will apply the slope formula:
m = (-8 - 27) / (5 - 0) = -7
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4 0
1 month ago
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An experiment was conducted to record the jumping distances of paper frogs made from construction paper. Based on the sample, th
tester [12383]

Answer:

9.9676 - 2.326*0.5904 =8.594

9.9676 + 2.326*0.5904 =11.341

Step-by-step explanation:

Notation

\bar X is the sample mean

\mu indicates the population mean (the variable of interest)

s signifies the sample standard deviation

n denotes the sample size

Solution to the problem

The mean's confidence interval is derived from the following formula:

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}   (1)

In this instance, the 9% confidence interval corresponds to:

8.8104 \leq \mu \leq 11.1248

We can determine the mean using the following:

\bar X = \frac{8.8104 +11.1248}{2}= 9.9676

Additionally, the margin of error can be calculated as:

ME= \frac{11.1248- 8.8104}{2}= 1.1572

The margin of error for this situation is expressed as:

ME = t_{\alpha/2}\frac{s}{\sqrt{n}} = t_{\alpha/2} SE

Next, we find the standard error:

SE = \frac{ME}{t_{\alpha/2}}

The critical value for a 95% confidence interval using a normal standard distribution is roughly 1.96, and substituting gives us:

SE = \frac{1.1572}{1.96}= 0.5904

For the 98% confidence interval, the significance corresponds to \alpha=1-0.98= 0.02 and \alpha/2 = 0.01 with a critical value of 2.326, yielding a confidence interval of:

9.9676 - 2.326*0.5904 =8.594

9.9676 + 2.326*0.5904 =11.341

8 0
1 month ago
Assume that the flask shown in the diagram can be modeled as a combination of a sphere and a cylinder. Based on this assumption,
Svet_ta [12734]

Answer:

Here’s the response provided

Step-by-step explanation:

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The volume of the cylinder can be calculated as πr²h = π(0.5)² × 3 = 2.36 in³

As for the sphere, its diameter is 4.5 in. Hence, the radius of the sphere R = diameter / 2 = 4.5/2 = 2.25 in

The volume of the sphere is calculated as 4/3 (πR³) = 4/3 × π × 2.25³ = 47.71 in³

The total volume of the flask = Volume of the cylinder  + Volume of the sphere = 2.36 + 47.71 = 50.07 in³

<pWhen the cylinder and the sphere are expanded by a scale factor of 2, the height (h') of the cylinder becomes 3/2 = 1.5 inches and the radius (r') becomes 0.5/2 = 0.025 inches.

The new volume for the cylinder = πr'²h' = π(0.25)² × 1.5 = 0.29 in³

For the sphere, the new radius is R' = 2.25 / 2 = 1.125 in.

The new volume of the sphere = 4/3 (πR'³) = 4/3 × π × 1.125³ = 5.96 in³

Thus, the new volume of the flask = The new volume of the cylinder  + The new volume of the sphere = 0.29 + 5.96 = 6.25 in³

<pThe ratio of the new volume to the original volume = New Volume of the flask / Volume of the flask = 6.25 / 50.07 = 1/8 = 0.125<pThe resulting volume will thus be 0.125 times the original volume

6 0
1 month ago
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I'm quite terrible at this aspect, so I'm merely making a guess.
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22 days ago
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Leona [12618]

Answer:

3\sqrt{5}/2

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we will use Pythagoras' theorem,

AC = \sqrt{AD^{2} + CD^{2} }

AC = 3\sqrt{5}/2

:-)

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1 month ago
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