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kykrilka
14 days ago
9

Nathaniel purchased a new car in 1997 for $20,300. The value of the car has been depreciating exponentially at a constant rate.

If the value of the car was $2,700 in the year 2004, then what would be the predicted value of the car in the year 2007, to the nearest dollar?
Mathematics
1 answer:
Zina [12.3K]14 days ago
6 0

Answer:

Step-by-step explanation:

We apply the exponential decay formula, which is represented as

A = P(1 - r)^t

Where

A signifies the car's value after t years.

t denotes the number of years.

P is the initial car value.

r signifies the decay rate.

Based on the provided information,

A = $2700

P = $20300

n = 2004 - 1997 = 7 years

Therefore,

20300 = 2700(1 - r)^7

20300/2700 = (1 - r)^7

7.519 = (1 - r)^7

Taking logarithms on both sides leads to

Log 7.519 = 7 log(1 - r)

0.876 = 7 log(1 - r)

Log (1 - r) translates to 0.876/7 = 0.125

By applying inverse logarithm, it results in

10^log1 - r equals 10^0.125

1 - r = 1.33

Thus, r = 1.33 - 1 = 0.33

We now have the expression

A = 20300(1 - 0.33)^t

A = 20300(0.67)^t

Thus, in 2007,

t = 2007 - 1997 = 10 years

The projected value equals

A = 20300(0.67)^10

A = $370

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