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1 month ago

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A 10 kg migratory swan cruises at 20 m/s. A calculation that takes into ac- count the necessary forces shows that this motion re

quires 200 W of mechanical power. If we assume an efficiency similar to humans (say, 25%), a reasonable assumption, then the metabolic power of the swan is significantly higher than this. The swan does not stop to eat during a long day of flying; it get the energy it needs from fat stores. Assuming an efficiency similar to humans, after 12 hours of flight, a. How far has the swan traveled? b. What fraction of its body mass does it lose? Assume that I g of fat contains 37 kJ of energy.

1 answer:

Ostrovityanka [3.2K]1 month ago

4 0

Response:

The total distance traveled by the swan amounts to

d = 864000 m

Portion of total mass that has been lost by it

$fraction = 0.0934$

Explanation:

Given that the swan flies at a speed of 20 m/s

Part a)

The swan's distance is determined by the product of speed and time

leading us to

$d = v t$

$d = 20 \times (12 \times 3600)$

$d = 864000 m$

Part b)

The power utilized by the swan is spoken of as 200 W

hence the total energy consumed over a span of 12 hours can be calculated as

$E = P \times t$

$E = 200(12 \times 3600)$

$E = 8.64 \times 10^6 J$

Given that the output power represents 25% of all energy utilized, the total energy consumed is interpreted as

$E_{net} = 3.456 \times 10^7 J$

As we understand that for every gram of fat, 37 kJ of energy is expended

the total mass lost in this

$m = \frac{3.456\times 10^7}{37 \times 10^3}$

$m = 934 g$

so the fraction of mass lost is computed as

$fraction = \frac{0.934}{10}$

$fraction = 0.0934$

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