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vlabodo
1 month ago
10

Which type radiation can be observed well from Earth's surface?

Physics
2 answers:
Sav [3.1K]1 month ago
6 0
Gamma Rays, due to their short wavelength and high frequency in the electromagnetic spectrum.
inna [3.1K]1 month ago
4 0
Electromagnetic radiation, commonly called visible light.
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Steel blocks A and B, which have equal masses, are at TA = 300 oC and T8 = 400 oC. Block C, with mc - 2mA, is at TC = 350 oC. Bl
serg [3582]

Answer:

b) TA = TB = TC

Explanation:

  • When the blocks are brought into contact and isolated from the environment, they will exchange heat until they achieve thermal equilibrium.
  • During this exchange, the hotter body will lose heat, which will be gained by the cooler body.
  • The equilibrium state will be established once this equation is satisfied:

       \Delta Q = c_{st}* m_{A} * (T_{fin} - T_{0A} ) = c_{st}* m_{B} * (T_{0B} - T_{fin} )

  • Substituting the initial temperatures T₀A = 300º C and T₀B = 400ºC, while simplifying for equal block masses mA = mB, enables us to solve for the final temperature, Tfin:

       (400 \ºC - T_{fin}) = (T_{fin} - 300 \ºC) \\ \\ 2* T_{fin} = 700\ºC\\ \\ T_{fin} = 350\ºC

  • At equilibrium, when both blocks combine, they will yield a uniform final temperature of 350ºC.
  • When block C, also at this temperature, makes contact, all three blocks will simultaneously reflect this final temperature of 350 ºC.
  • Therefore, option b) is correct.
8 0
2 months ago
A coin with a diameter 3.00 cm rolls up a 30.0 inclined plane. The coin starts out with an initial angular speed of 60.0 rad/s
ValentinkaMS [3465]
This question is incomplete. The query is regarding a 3.00 cm diameter coin rolling up a 30.0° incline. With an initial angular speed of 60.0 rad/s, it rolls without slipping. Given that the moment of inertia of the coin is (1/2) MR², the distance the coin travels up the incline is calculated as 0.124 m.
6 0
1 month ago
The acceleration due to gravity on the moon is 1.6 m/s2, about a sixth that of Earth’s. Which accurately describes the weight of
kicyunya [3294]

Response:

The question is not fully provided; here is the complete context:

Gravity's acceleration on the moon is 1.6 m/s², roughly one-sixth that of Earth's. What is the accurate description of an object's weight on the moon?

A. An object on the moon is lighter by a factor of 1/6 compared to Earth.

B. An object on the moon is heavier by a factor of 1/6 compared to Earth.

C. An object on the moon is six times lighter than on Earth.

D. An object on the moon is six times heavier than on Earth.

The correct choice is:

An object on the moon is six times lighter than on Earth. (C)

Explanation:

The acceleration resulting from gravity indicates how a gravitational force impacts an object, causing it to accelerate. This is a vectorial quantity because it possesses both magnitude and direction, measured in the unit of m/s². On Earth, this gravitational acceleration is represented by the letter g and its value is approximately 9.8m/s².

The larger size of the Earth in comparison to the moon causes its gravitational acceleration to be about six times greater than that of the moon, resulting in the moon's gravitational acceleration being approximately 1.6m/s².

Next, weight refers to the product of mass and gravity's acceleration. This reflects the gravitational pull acting upon a mass, which is also measured in Newtons, similar to force.

Weight = m × g (N)

From the weight formula, we can see that weight corresponds directly to mass and gravitational acceleration:

weight ∝ mass;

weight ∝ gravitational acceleration.

This implies that if gravitational acceleration increases, weight increases as well, and vice versa.

For instance, let's calculate the weights of a 10kg object on both Earth and the moon.

Gravitational acceleration on Earth (g₁) = 9.8m/s².

Gravitational acceleration on the moon (g₂) = 1.6m/s².

On Earth:

weight = m × g₁ = 10 × 9.8 = 98 N.

On the moon:

weight = m × g₂ = 10 × 1.6 = 16 N.

From the above example, since the acceleration due to gravity on the moon is 1/6 that of Earth, the weight of a 10kg object on the moon is approximately six times lighter (16 N) than its weight on Earth (98 N).

5 0
2 months ago
Read 2 more answers
A car is moving down a flat, horizontal highway at a constant speed of 21 m/s when suddenly a rock dropped from rest straight do
Keith_Richards [3271]

Answer:

a)9.8

Explanation:

because any object falling from any height experiences 9.8

(sorry that's all I know)

7 0
2 months ago
The crossbar of a goal post on a professional American football field sits at a height of 3.05 meters (10 feet) above the field.
Sav [3153]

Answer:

A. Yes, the ball clears the crossbar by 2.83 meters

Explanation:

This situation pertains to projectile motion.

The horizontal velocity component of the ball is calculated as 26 cos 35 = 21.3 m/s

The vertical velocity component is 26 sin 35 = 14.9 m/s

The time taken to travel the horizontal distance to the goalpost, which is 54.9 m, is:

= distance / horizontal speed

= 54.9 / 21.3

= 2.577 seconds.

The vertical distance achieved during this time is:

h = ut - 1/2 gt², where u is the initial vertical velocity, and t = 2.577 seconds.

h = 14.9 x 2.577 - 0.5 x 9.8 x (2.577)²

= 38.39 - 32.54

= 5.85 m

Thus, the ball surpasses the crossbar by 5.85 - 3.05 = 2.8 m

5 0
2 months ago
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