Answer:
The cross-sectional area of the larger piston is 392cm ^{2}[/tex]
Explanation:
To find the solution, we apply the following equation:
Pascal's principle: F=P*A Formula (1)
F=Force applied to the piston
P: Pressure
A= Area of the piston
Nomenclature:
Fp= Force on the primary piston= 500N
W= weight of the car =m*g=2000kg*9.8m/s2= 19600N
Fs= Force on the secondary piston= W = 19600N
As= Area of the secondary piston=?
Pressure applied on one side is distributed to all liquid molecules since liquids are incompressible.
From equation (1)
P=F/A
Pp=Ps
Answer:
v_y = 12.54 m/s
Explanation:
Given values:
- Initial vertical height y_o = 10 m
- Initial velocity v_y,o = 0 m/s
- The object's acceleration in the air = a_y
- The actual time taken to reach the ground t = 3.2 s
Find:
- How to calculate the object's speed when it arrives at the ground?
Solution:
- Apply kinematic equations to find the actual acceleration of the ball when it reaches the ground:
y = y_o + v_y,o*t + 0.5*a_y*t^2
0 = 10 + 0 + 0.5*a_y*(3.2)^2
a_y = - 20 / (3.2)^2 = 1.953125 m/s^2
- Use the total energy conservation principle of the system:
E_p - W_f = E_k
Where, E_p = m*g*y_o
W_f = m*a_y*(y_i - y_f)..... Reflecting air resistance
E_k = 0.5*m*v_y^2
Thus, m*g*y_o - m*a_y*(y_i - y_f) = 0.5*m*v_y^2
g*(10) - (1.953125)*(10) = 0.5*v_y^2
v_y = sqrt(157.1375)
v_y = 12.54 m/s
Answer:
The period of a wave is the duration it takes to complete one full oscillation, such as from one peak to the next trough.
Since the period is expressed in microseconds, it needs to be converted into seconds.
The conversion is:
Accordingly, the wave's period in seconds is .
It may lead to higher levels of homocysteine, which can harm the inner linings of arteries. Such damage often results from unwanted clotting that can occur due to factors like smoking, which tends to raise unwanted blood clots in the body, ultimately causing these levels to rise and resulting in undesired consequences.
