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Rus_ich
3 months ago
15

During a hockey game on a pond, the defenseman passes a 114-g hockey puck over the ice to the center, who fails to catch it. the

puck is traveling at an inital speed of 6.7 m/s. it stops in 18 m due to the frictional force on it from the ice. find the magnitude of the frictional force on the ice
Physics
1 answer:
Sav [3.1K]3 months ago
8 0
The frictional force is calculated as f = 0.1421 N. In the context of the hockey puck's motion, we apply the equation for uniformly accelerated motion: vf² = v₀² + 2ad. Given the initial velocity, final velocity, and displacement, we determine the acceleration, which subsequently leads us to calculate the frictional force acting on the puck.
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A 9.0-V battery moves 20 mC of charge through a circuit running from its positive terminal to its negative terminal. How much en
Yuliya22 [3333]

Answer:

The energy delivered is E = 0.18 J

Explanation:

Given,

Battery voltage, V = 9 V

Charge in the circuit, Q = 20 mC

                                        = 20 x 10³ C

Energy supplied in the circuit can be computed as

E = Q V

E = 20 x 10⁻³ x 9

E =  180 x 10⁻³

E equals 0.18 J.

The energy delivered in the circuit is therefore E = 0.18 J

7 0
2 months ago
A wildlife researcher is tracking a flock of geese. The geese fly 4.0 km due west, then turn toward the north by 40° and fly ano
serg [3582]

Answer:

(a). The distance traveled is 7.06 km towards the west.

(b). Their displacement magnitude is 7.51 km.

Explanation:

The information given states that,

The geese initially move 4.0 km directly west, then alter course to the north at a 40° angle, covering an additional 4.0 km.

Based on the diagram,

(a). To determine the distance

We will apply the distance formula

AD=AB+BD

Insert the values into the equation

D= 4+4.0\cos40^{\circ}

D=7.06\ km

The resultant distance is 7.06 km westward.

(b). We will find the total displacement's magnitude

Using the displacement formula

AC=\sqrt{(CD)^2+(AD)^2}

Insert the values into the equation

AC=\sqrt{(4.0\sin40)^2+(7.06)^2}

AC=7.51

The total displacement magnitude is 7.51 km.

In conclusion, (a). The traveled distance is 7.06 km towards the west.

(b). The magnitude of their total displacement is 7.51 km.

7 0
3 months ago
a force of 6lbs acts on an object with a weight of 35 lbs on earth. determine the objects acceleration. final answer must be 5.5
kicyunya [3294]
Weight of the object = 35 lbs
F = ma
m = F/a = 35/32 (with acceleration of 32 ft/s²)
m= 1.09

Again applying the same formula,
a = F/m
a= 6/1.09
a= 5.489

Thus, the acceleration is approximately 5.5 ft/s²!!
5 0
3 months ago
Read 2 more answers
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