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Flauer
14 days ago
5

3. You measure a cube and determine that its sides are 0.65m. You place the cube on a mass scale and determine that this cube ha

s a mass of 10,500 grams. What is the density of this cube in units of kg/m3 and in units of g/mL?
Chemistry
1 answer:
KiRa [2.9K]14 days ago
7 0
The density of the cube is calculated as follows: 38.234 kg/m³ or 0.038234 g/mL. Explanation: We begin with the formula for volume, which is expressed as m³ where 'm' indicates the side of the cube. Given that the cube’s side is 0.65 m and its mass measures 10,500 grams, this converts to 10.5 kg (as 1000 grams = 1 kg). The volume is calculated as (0.65)³, equaling 0.274625 m³. Density is determined by dividing mass by volume, leading to a density of 10.5 kg divided by 0.274625, resulting in 38.234 kg/m³. To convert, 1 kg/m³ equals 0.001 g/mL, thus resulting in 0.038234 g/mL.
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How to correctly solve this problem : 4.05Kg+567.95g+100.1g correct and best way
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Refer to the attached document for the solution.

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1 month ago
The two-slit diffraction experiment shows how light can be treated as particles and how light waves carry the statistical inform
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The double-slit experiment serves as a renowned method to exemplify concepts in quantum mechanics. Specifically, it highlights the idea of wave-particle duality. Employing a light wave shows diffraction and interference, which are typical characteristics of wave behavior. Unexpectedly, using an electron beam produces an interference pattern as well, indicating that electrons can exhibit wave-like properties.


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Answer:

C) 1.15 × 10⁻⁷ mm

Explanation:

Step 1: Provided information

Average separation between oxygen and nitrogen atoms: 115 pm

Step 2: Change the distance to meters (SI standard unit)

Using the conversion 1 m = 10¹² pm.

115 pm × (1 m/10¹² pm) = 1.15 × 10⁻¹⁰ m

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12 days ago
What is the total number of atoms in 0.20 mol of propanone, CH3COCH3?
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Answer:

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Explanation:

In the problem, we see the data:

Mole of propanone = 0.20 mole

Calculating the number of atoms in propanone =?

According to Avogadro's principle, one mole of a substance contains 6.022×10²³ atoms.

This means that one mole of propanone also holds 6.022×10²³ atoms.

Thus, we can determine the atom count in 0.20 mole of propanone as:

1 mole of propanone contains 6.022×10²³ atoms.

Accordingly, 0.20 mole of propanone will have = 0.2 × 6.022×10²³ = 1.2×10²³ atoms.

Therefore, 0.20 mole of propanone contains

1.2×10²³ atoms.

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12 days ago
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