Ask question

Ask question

All categories

8 days ago

13

Carbonic acid, H2CO3, has two acidic hydrogens. A solution containing an unknown concentration of carbonic acid is titrated with

potassium hydroxide. It requires 20.0 mL of 3.840 M KOH solution to titrate both acidic protons in 50.2 mL of the carbonic acid solution.
1. Write a balanced net ionic equation for the neutralization reaction. Include physical states.
2. Calculate the molarity of the carbonic acid solution.

1 answer:

KiRa [971]8 days ago

6 0

Answer:

1) The net ionic equation:

$2H^+(aq)+2OH^-(aq)\rightarrow 2H_2O(l)$

2) The molarity of the carbonic acid solution equals 0.765 M.

Explanation:

1) In aqueous carbonic acid, both carbonate ions and hydrogen ions exist:

$H_2CO_3(aq)\rightarrow 2H^+(aq)+CO_3^{2-}(aq)$ ..[1]

In potassium hydroxide solution, potassium ions and hydroxide ions are found:

$KOH(aq)\rightarrow K^+(aq)+OH^{-}(aq)$ ..[2]

In potassium carbonate solution, potassium ions and carbonate ions are present:

$K_2CO_3(aq)\rightarrow 2K^+(aq)+CO_3^{2-}(aq)$ ..[3]

$H_2CO_3(aq)+2KOH(aq)\rightarrow K_2CO_3(aq)+2H_2O(l)$

From these:[1], [2], and [3]:

$2H^+(aq)+CO_3^{2-}(aq)+2K^+(aq)+2OH^{-}(aq)\rightarrow 2K^+(aq)+CO_3^{2-}(aq)+H_2O(l)$

To formulate the net ionic equation, eliminate common ions on both sides:

$2H^+(aq)+2OH^-(aq)\rightarrow 2H_2O(l)$

2)

For determining acid concentration, utilize the equation from the neutralization reaction:

$n_1M_1V_1=n_2M_2V_2$

In which,

$n_1,M_1\text{ and }V_1$ indicates the n-factor, molarity and volume related to acid represented as $H_2CO_3$ .

$n_2,M_2\text{ and }V_2$ indicates n-factor, molarity and volume concerning the KOH base.

Provided information includes:

$n_1=2\\M_1=?\\V_1=50.0 mL\\n_2=1\\M_2=3.840 M\\V_2=20.0 mL$

By plugging in these values to the equation, we find:

$M_1=\frac{1\times 3.840 M\times 20.0 mL}{2\times 50.2 mL}=0.765 M$

The molarity of the carbonic acid solution is found to be 0.765 M.

You might be interested in

The metallic radius of a lithium atom is 152 pm. What is the volume of a lithium atom in cubic meters?

eduard [944]

Answer:

The calculated volume of a lithium atom is 1.47 X 10⁻²⁹ m³.

Explanation:

Assuming the atom's volume is spherical (though it’s actually more complex), the volume is mathematically represented by:

$V=\frac{4}{3}\pi R^{3}$ ----------------------------------------------------------------------------------------(Eq. 1)

Here, R corresponds to the lithium atom's radius. Since the radius is provided in picometers, we first convert it into meters.

$R=(152pm )(1X10^{-12}\frac{m}{pm})$

$R = 1.52 X 10^{-10}m$

Substituting this value into Eq.1 provides the desired result.

$V=\frac{4}{3}\pi {1.52X10^{-10}}^{3}$

V= 1.47 X 10⁻²⁹ m³

8 0

8 days ago

If an ionic compound were composed of a4+ and b−, which unit cell structure would give a neutral compound?

lions [985]

<span>These are biological processes taking place in cells, while simplifying the intricate interactions found in complete cells. Both eukaryotic and prokaryotic cells have been utilized to develop these simplified systems[1]. By employing ultracentrifugation, subcellular fractions can be separated, producing the molecular components needed for reactions without many other cellular elements. Biosystems that do not require cells can be created by combining various purified enzymes and coenzymes. These cell-free biosystems are being considered as a cost-effective alternative for biomanufacturing compared to traditional microbial fermentation methods that have been in use for centuries. They offer multiple advantages that make them appealing for industrial purposes.</span>

4 0

5 days ago

The graph above shows the changes in temperature recorded for the 2.00 l of h2o surrounding a constant-volume container in which

Alekssandra [968]

Answer:

25.2 kJ

Explanation:

The full question can be found in the image linked to this response.

It's important to highlight that the heat absorbed by the 2.00 L of water for increasing its temperature from the beginning to the end comes solely from the burning of benzoic acid, as there are no heat transfers to the container or the surroundings.

To find the heat released from benzoic acid combustion, we simply measure the heat needed to warm the water.

Q = mCΔT

To find the mass of the water,

Density = (mass)/(volume)

Mass = Density × volume

Density = 1 g/mL

Volume = 2.00 L = 2000 mL

Mass = 1 × 2000 = 2000 g

C = specific heat of water = 4.2 J/g.°C

ΔT = (final temperature) - (Initial temperature)

<pAccording to the graph,

Final water temperature = 25°C

Initial water temperature = 22°C

ΔT = 25 - 22 = 3°C

Q = (2000×4.2×3) = 25,200 J = 25.2 kJ

Hope this Helps!!!

6 0

8 days ago

Suppose you need of Grade 70 tow chain, which has a diameter of and weighs , to tow a car. How would you calculate the mass of t

VMariaS [1037]

Answer: refer to the explanation

Explanation:

This question requires calculating mass. To determine the mass, we need values for two parameters, namely the specifications for the grade 70 tow chain and the mass per unit length given.

Assuming the mass per unit length is 3 kilograms per meter (kg/m) and the length of the grade 70 tow chain is 5 meters (m).

Thus, the formula used to compute the mass of the chain is as follows;

Mass of the chain = mass per unit length (kg/m) × length ---------------------------------------------------------------------------------------------------------------------(1).

Mass of the chain = 3 kg/m × 5 m.

Mass of the chain equals 15 kg.

7 0

6 days ago

You are given a piece of paper and a match. The paper has a mass of 2.5 g. You then light the match and light the piece of paper

KiRa [971]

Answer:

No

Explanation:

No. The demonstration in question does not infringe upon the conservation of mass.

The law of conservation of mass states that mass cannot be created or destroyed in a chemical reaction; however, mass can change from one form to another during the process.

In this instance, although the remnants of the paper weigh 0.5 g compared to the original weight of 2.5 g, the ashes and gases produced during combustion account for the missing mass of the paper.

The portion that has been burnt has transformed into other states. If the gas and ashes are adequately contained, they will correspond to the weight of the original paper when added to the remaining paper.

5 0

1 day ago