Answer:
The answer to the specified question will be "
".
Explanation:
Referring to the question,
⇒ 
⇒ 
...(equation 1)
⇒ 
⇒ 
...(equation 2)
Now,
From equation 1 and equation 2, we conclude
⇒ 
By substituting the value of 
, we derive
⇒ 
⇒
The correct term is accretion disk. This refers to a formation, typically a circumstellar disk, created by dispersed matter revolving around a large central body, which is usually a star. The gravitational pull causes the material in the disk to spiral inward towards the center.
Response:
C. vx
F. ax
G. ay
Clarification:
The projectile follows a curved trajectory toward the ground, causing changes in x and y positions.
Since there is no external force acting in the x-direction, the acceleration in x remains at zero. Consequently, ax and vx remain unchanged.
The projectile is subject to the force of gravity, directed downwards, leading to an increase in its velocity due to the rise in its y-component.
Meanwhile, the y-component of acceleration remains constant due to gravitational acceleration.
F = π/4 ρ d² v²
Explanation:
The formula for force is mass multiplied by acceleration:
F = ma
Acceleration is defined as the change in velocity over the change in time:
F = m Δv / Δt
Since there is no rebound effect, Δv is equal to v.
F = m v / Δt
Mass can be calculated as density multiplied by volume:
F = ρ V v / Δt
Flow rate describes the volume per time:
F = ρ Q v
Flow rate is determined by velocity multiplied by the cross-sectional area:
F = ρ (v A) v
This simplifies to F = ρ A v²
The area of a circle is calculated as pi times the square of the radius, or as pi/4 times the diameter squared:
F = ρ (π/4 d²) v²
Hence, F = π/4 ρ d² v²
As the parachutist is descending at a steady rate
we can conclude that
Acceleration indicates the change in velocity
given the constant velocity in this scenario
Thus, in this situation, we find the acceleration to be zero
It’s understood from Newton's second law
where a is equal to 0
Here, the force due to gravity
equals the force due to buoyancy
Hence, we can deduce
therefore
as such the upward force is counteracted by the downward force.
