answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
jekas
7 days ago
12

Point m is located a distance 2d from the midpoint between the two wires. find the magnitude of the magnetic field b1m created a

t point m by wire 1.

Physics
1 answer:
Sav [2.8K]7 days ago
3 0

Reminder: The illustration mentioned in the inquiry is included here as a file.

Response:

The intensity of the magnetic field is B = \frac{0.071 \mu I}{d}

Clarification:

The magnetic field can be calculated using the following equation:

B = \frac{\mu I}{2\pi R}...............(1)

Where I refers to the current flowing through the wires

To find the distance R from point 1 to m, apply the Pythagorean theorem

R = \sqrt{d^{2} + (2d)^{2} }

R = \sqrt{5d^{2} } \\R = d\sqrt{5}

Inserting R into equation (1)

B = \frac{\mu I}{2\pi d\sqrt{5} }

B = \frac{0.071 \mu I}{d}

You might be interested in
Two projectiles are launched with the same initial speed from the same location, one at a 30° angle and the other at a 60° angle
Ostrovityanka [2814]

Answer:

Explanation:

Let us denote the launch angle as \theta _1=30^{\circ}.

\theta _2=60^{\circ}, \theta _1, and \theta _2 are complementary angles which means their ranges are identical.

H_{max}=\frac{u^2(\sin \theta )^2}{2g}

H_{30}=\frac{u^2(\sin 30)^2}{2g}

H_{30}=\frac{u^2}{8g}

Time of flight is indicated as =\frac{2u\sin \theta }{g}.

t_{30}=\frac{u}{g}

For \theta =60^{\circ}

H_{60}=\frac{u^2(\sin 60)^2}{2g}

H_{60}=\frac{3u^2}{8g}

t_{60}=\frac{2u\sin 60}{g}=\frac{\sqrt{3}u}{g}

H_{60}=3\times H_{30}

t_{60}=\sqrt{3}\times t_{30}

7 0
28 days ago
A proton is released from rest at the origin in a uniform electric field that is directed in the positive xx direction with magn
Ostrovityanka [2814]
The alteration in potential energy is  \Delta PE = - 3.8*10^{-16} \ J

In the query, it is stated that

  The intensity of the uniform electric field equals E = 950 \ N/C

     The distance the electron covers is  x = 2.50 \ m

Typically, the force exerted on this electron is expressed mathematically as

     F = qE

Where F signifies the force and  q represents the charge of the electron, which is a fixed value of q = 1.60*10^{-19} \ C

    Thus  

      F = 950 * 1.60 **10^{-19}

      F = 1.52 *10^{-16} \ N

Generally, the work-energy theorem is mathematically framed as

          W = \Delta KE

Where W denotes the work done on the electron by the electric field and  \Delta KE  is the change in kinetic energy

Additionally, work done on the electron can also be described as

        W = F* x *cos( \theta )

Where  \theta = 0 ^o assuming that the electron's movement aligns with the x-axis  

        So

             \Delta KE = F * x cos (0)

Inserting values

         \Delta KE = 1.52 *10^{-16} * 2.50 cos (0)

          \Delta KE = 3.8*10^{-16} J

According to the conservation of energy

       \Delta PE = - \Delta KE

Where \Delta PE signifies the change  in  potential energy  

Thus  

        \Delta PE = - 3.8*10^{-16} \ J

               

7 0
10 days ago
Potential energy matter has a result of its ____ or ____.
Yuliya22 [2962]
Position or composition
3 0
25 days ago
Read 2 more answers
What is the sources of error and suggestion on how to overcome it in the hooke's law experiment?
Yuliya22 [2962]
In the study of physics, Hooke's law can be expressed as:

F = kx

This law indicates that the spring force F is proportional to the extension x, with k being the spring constant.

In experiments, this is often examined using the setup illustrated in the included figure. The spring is tested, and a known weight is applied underneath it. This weight exerts a gravitational pull, essentially its weight, on the spring. While the spring elongates, the displacement can be measured using a ruler.

Several potential errors can arise during this experiment. Firstly, the person's measurement reading may be faulty. Digital scales offer greater accuracy as they reduce human error, while ruler readings can be subjective, especially if not viewed at eye level. Additionally, the object's weight may be inaccurately measured if the scale is untrustworthy. Lastly, the measuring equipment may not be correctly calibrated.

6 0
1 month ago
Which characteristics of Earth’s orbit are in agreement with Kepler’s second law? Check all that apply.
Maru [2973]

Here is an image displaying the correct answers.

6 0
26 days ago
Read 2 more answers
Other questions:
  • Reset the PhET simulation (using the button in the lower right) and set it up in the following manner: select Oscillate, select
    15·1 answer
  • A cylindrical tank of methanol has a mass of 40 kgand a volume of 51 L. Determine the methanol’s weight, density,and specific gr
    10·1 answer
  • The magnitude of the force associated with the gravitational field is constant and has a value FF . A particle is launched from
    14·1 answer
  • Estimate the monthly cost of using a 700-W refrigerator that runs for 10 h a day if the cost per kWh is $0.20.
    12·1 answer
  • Snowboarder Jump—Energy and Momentum
    9·1 answer
  • A current of 0.001 A can be felt by the human body. 0.005 A can produce a pain response. 0.015 A can cause a loss of muscle cont
    9·1 answer
  • A fire hose held near the ground shoots water at a speed of 6.5 m/s. At what angle(s) should the nozzle point in order that the
    12·1 answer
  • A charge Q is distributed uniformly along the x axis from x1 to x2. What would be the magnitude of the electric field at x0 on t
    8·1 answer
  • A 10.0 cm3 sample of copper has a mass of 89.6
    12·1 answer
  • Complete the T-chart by categorizing each environmental factor as something that would most likely increase or decrease genetic
    8·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!