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1 day ago

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Scientists in the jungle want to find the best estimate for the lion population. They tagged and released 20 lions as part of a

research project. Later, they found 160 lions, 8 of which were tagged? Find the best estimate of population?

1 answer:

Inessa [12.2K]1 day ago

3 0

Answer:

They anticipate the following ratio:

x/20 = 160/8, where x represents the population

Next

x = 20×160/8 = 400

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En una cancha se va a pintar la circunferencia central que tiene un diámetro de 5 m .¿cual es la longitud de la circunferencia?

Leona [12186]

Answer:

The measurement of the circumference is $5\pi\ m$ or $15.70\ m$

Step-by-step explanation:

The inquiry in English is

On a court, the main circumference is to be painted, with a diameter of 5 m. What is the circumference length?

we understand that

The circumference of a circle can be calculated with the formula

$C=\pi D$

we possess

$D=5\ m$

replace

$C=\pi (5)\\C=5\pi\ m$

This results in the precise measurement

let's consider

$\pi=3.24$

$C=5(3.14)=15.70\ m$

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1 month ago

if Marianne's father calls and says he needs 13 pounds of potting soil, how many additional bags should she buy?

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THE RESULT WOULD BE 10 MORE BAGS

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1 month ago

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Let an integer be chosen at random from the integers 1 to 30 inclusive. Find the probability that the integer chosen is not even

babunello [11358]

Given that the sequence goes odd, even, odd, and even , there is an equal chance of drawing an odd (<span>not divisible by 2) number as there is for drawing an even number, so the correct option is C.

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4 days ago

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Sarah can bicycle a loop around the north part of Lake Washington in 2 hours and 30 minutes. If she could increase her average s

Leona [12186]

Response:

The loop's length is roughly 49.58 km.

Step-by-step details:

Given:

Duration to cycle the loop = 2 hours and 30 minutes

It is known that;

60 minutes = 1 hour

30 minutes = 0.5 hour

therefore, 2 hours and 30 minutes = $2+0.5 = 2.5\ hrs$

∴ Time to cycle the loop = 2.5 hours

Let 's' denote the cycling speed.

Denote the total loop distance as 'd'

From our understanding;

Distance equals speed times time.

Representing this as an equation we have;

$d =2.5s \ \ \ \ equation \ 1$

Given:

If her speed increased by 1 km/hr, the time taken around the loop would decrease by 7 minutes.

As a result, we can say;

Speed = $s+1$

The time then will be shortened by 7 minutes.

7 minutes = 0.12 hours

Consequently, time = 2.5 - 0.12 = 2.38

Again, Distance is calculated as speed times time.

This can be expressed with equations;

$d =2.38(s+1) \ \ \ \ equation \ 2$

The distances are equivalent in both scenarios, thus we will determine speed by equating the equations.

$2.5s = 2.38(s+1)\\\\2.5s=2.38s+2.38\\\\2.5s-2.38s =2.38\\\\0.12s= 2.38\\\\s =\frac{2.38}{0.12} \approx 19.83\ km/hr$

So, Speed = 19.83 km/hr

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Therefore, the loop length is approximately 49.58 km.

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1 month ago

Use the normal approximation to the binomial distribution to answer this question. Fifteen percent of all students at a large un

AnnZ [11983]

Answer: 0.1289

Step-by-step explanation:

Given: The proportion of students absent on Mondays at a large university.: $p=0.15$

Sample size: $n=12$

Mean: $\mu=np=12\times0.15=1.8$

Standard deviation = $\sigma=\sqrt{np(1-p)}$

$\Rightarrow\ \sigma=\sqrt{12(0.15)(1-0.15)}=1.23693168769\approx1.2369$

Let x represent a binomial variable.

Referencing the standard normal distribution table,

$P(x=4)=P(x\leq4)-P(x\leq3)$ (1)

Z score for normal distribution:-

$z=\dfrac{x-\mu}{\sigma}$

For x=4

$z=\dfrac{4-1.8}{1.2369}\approx1.78$

For x=3

$z=\dfrac{3-1.8}{1.2369}\approx0.97$

Thus, from (1)

$P(x=4)=P(z\leq1.78)-P(z\leq0.97)\\\\=0.962462-0.8339768\approx0.1289$

Consequently, the likelihood of four students being absent = $0.1289$

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1 month ago