A very tall building has a height H0 on a cool spring day when the temperature is T0. You decide to use the building as a sort o
1 answer:
Response:
The temperature is
Justification:
According to the information provided in the question,
The height on a cool spring day measures
The temperature for a cool spring day registers as
The height variation between a cool spring day and a summer day is accounted as h
The static friction coefficient stands at
The equation outlining the linear expansion for the steel building is given as
In this case, T represents the steel's temperature during summer
Rearranging for T, we derive
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Answer:
The equivalent distance in kilometers is 4012 × km.
Explanation:
It's known that 1 millimeter converts to meters. Then, 1 meter converts to
kilometers. Therefore, the conversion for 1 millimeter to kilometers can be stated as
1 mm = m
1 m = km
Thus, 1 mm = ×
km =
km.
Given the distance of 4012 mm, the corresponding distance in kilometers will be
4012 mm = 4012 × km.
The distance therefore is 4012 × km.