Response:
a) , b)
Clarification:
a) The absolute pressure at a depth of 27.5 meters is:
b) The force applied by the water is:
A very tall building has a height H0 on a cool spring day when the temperature is T0. You decide to use the building as a sort o
1 answer:
Response:
The temperature is
Justification:
According to the information provided in the question,
The height on a cool spring day measures
The temperature for a cool spring day registers as
The height variation between a cool spring day and a summer day is accounted as h
The static friction coefficient stands at
The equation outlining the linear expansion for the steel building is given as
In this case, T represents the steel's temperature during summer
Rearranging for T, we derive
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Answer:
1/7 kg
Explanation:
Refer to the attached diagram for enhanced clarity regarding the question.
One of the blocks weighs 1.0 kg and accelerates downward at 3/4g.
g denotes the acceleration due to gravity.
Let M represent the block with known mass, while 'm' signifies the mass of the other block and 'a' refers to the acceleration of body M.
Given M = 1.0 kg and a = 3/4g.
By applying Newton's second law;
For the body with mass m;
T - mg = ma... (1)
For the body with mass M;
Mg - T = Ma... (2)
Combining equations 1 and 2 gives;
+Mg -mg = ma + Ma
Ma-Mg = -mg-ma
M(a-g) = -m(a+g)
Substituting M = 1.0 kg and a = 3/4g into this equation leads to;
3/4 g-g = -m(3/4 g+g)
3/4 g-g = -m(7/4 g)
-g/4 = -m(7/4 g)
1/4 = 7m/4
Multiplying gives: 28m = 4
m = 1/7 kg
Hence, the mass of the other box is 1/7 kg
Answer:
The tension in the string when the speed increased is 134.53 N
Explanation:
Given;
Tension in the string, T = 120 N
initial speed of the transverse wave, v₁ = 170 m/s
final speed of the transverse wave, v₂ = 180 m/s
The wave speed is expressed as;
where;
μ represents mass per unit length
The new tension T₂ will be computed as;
Consequently, the tension in the string when the speed was increased is 134.53 N