Implicit differentiation: remember that dy/dx y = dy/dx, so take the derivative of both sides. To solve for the derivative, subtract 2x from both sides, then divide by 2y. When considering the slope, solve for it and determine where the circle intersects with the line. Substitute for y and proceed by multiplying both sides. Take the square root of both sides, accounting for both positive and negative roots, leading to x = ±10. Thus, the points located are (10,-24) and (-10,24).
Respuesta:
-0.7
Explicación paso a paso:
Puedes elegir cualquier dígito para 
y 
pero la diferencia debe ser 0.7. Elegí 1.0 y 0.3.
Given:
In triangle GHJ, the angles measure ∠G = 110°, ∠J = 40°, and ∠H = 30°.
To find:
The response to finish the provided statements.
Solution:
Based on the relationship between angles and sides in a triangle, the largest angle corresponds to the longest opposite side while the smallest angle corresponds to the shortest side.
We know that ∠G = 110°, ∠J = 40°, and ∠H = 30°.
Here, it is clear that ∠G is greater than both ∠J and ∠H, confirming that it is the largest angle.
Since angle G is the largest, side JH is the longest.
Clearly,
110° > 40° > 30°.
Thus, ∠G > ∠J > ∠H
Following the triangle's side and angle relationship leads to the conclusion:
JH > GH > GJ
The arrangement of side lengths from the longest to the shortest is JH, GH, and GJ.
Total weight = 50 lb
x = count of 3-lb weights
y = count of 10-lb weights
weight from 3-lb weights = 3x
weight from 10-lb weights = 10y
overall weight = 3x + 10y
equation
3x + 10y = 50
Answer:
100+20π
Step-by-step explanation:
Refer to the attached diagram.
Perimeter of a square = 4L
where L represents the length of a square's side
According to the diagram;
L = 10
Thus, Perimeter of one square = 4(10) = 40
Consequently, the perimeter of three squares combined = 3(40) = 120
Two semicircles create one full circle
The perimeter of a circle is given by the formula 2πr
Here, the radius of the circle equals the length of a side of the square.
Area of the circle = 2π(10)= 20π
The complete perimeter of the shape is therefore the perimeter from the two semicircles combined with that of the four squares = 100+20π
