Which of the following is a true statement about cloud computing?

Answer:

This is the JAVA code:

import java.util.Scanner; // to obtain user input

//class designed to count occurrences of a character within a string

public class CharacterCounter

//method that calculates how many times a character appears within a string

{ public static int CountCharacter(String userString, char character)

   {  

       int counter = 0;   //keeps track of the number of times the character appears in the string

for (int i=0; i<userString.length(); i++) //iterates over every character in the string

       { // if the character aligns with the one sought in the string

           if (userString.charAt(i) == character)

           counter++;  // increments the character count variable

       }  

       return counter;     } // returns the count of the character found in the string

public static void main(String[] args) {

    Scanner scanner = new Scanner(System. in);// accepts user input

    String string;

    char character;

       System.out.println("Enter a string"); // prompts the user for a string

       string = scanner.nextLine(); //captures the input string

       System.out.println("Enter a character");

       // requests the character input from the user

       character = scanner.next().charAt(0); //captures and reads the character

       System.out.println("number of times character "+character + " appears in the string " + string +": " + CountCharacter(string, character));  }  }

// calls CountCharacter method to display the frequency of a character in the input string

Explanation:

The CountCharacter() method contains a loop where index variable i traverses through each character of the string, incrementing the counter variable by 1 each time the sought character matches. This indicates that the counter maintains the tally of occurrences of the character in the string. The loop terminates when i exceeds the string length, which means the full string has been scanned for the specified character. Finally, the count variable yields the number of times the character was found in the string. The main() function receives user inputs for a string and a character to search for within that string. It subsequently invokes the CountCharacter() function to determine how many times the designated character appears in the specified string, displaying the result on the screen.

The program's output is provided in the attached screenshot.

Answer:

The answer is B.

Explanation:

The justification for choosing B is that "bytes" represent the correct method for storing data in binary form of 0s and 1s.

Answer:

C3H8

Explanation:

Step 1:

Relevant details from the question are noted below:

Mass of the alkane is 1.17g

Volume (V) = 674 mL

Temperature (T) = 28°C

Pressure (P) = 741 mmHg.

Gas constant (R) = 0.08206 atm.L/Kmol

Step 2:

Convert to the appropriate units.

For Volume:

1000mL = 1L

So, 674mL = 674/1000 = 0.674L

For Temperature:

Temperature in Kelvin = Temperature in Celsius + 273

Temperature in Celsius = 28°C

Temperature in Kelvin = 28°C + 273 = 301K

For Pressure:

760mmHg = 1atm

So, 741 mmHg = 741/760 = 0.975atm

Step 3:

Calculate the moles of the alkane.

The moles of the alkane can be found using the ideal gas equation, presented below:

Volume (V) = 0.674L

Temperature (T) = 301K

Pressure (P) = 0.975atm

Gas constant (R) = 0.08206 atm.L/Kmol

Number of moles (n) =?

PV = nRT

n = PV /RT

n = (0.975 x 0.674)/(0.08206x301)

n = 0.0266 moles

Step 4:

Calculate the alkane’s molar mass.

Mass of alkane = 1.17g

Number of moles = 0.0266moles

Molar Mass =?

Number of moles = Mass/Molar Mass

Molar Mass = Mass/Number of moles

Molar Mass of alkane = 1.17/0.0266 = 44g/mol

Step 5:

Determine the molecular formula of the alkane.

This is based on:

The general formula for alkanes is CnH2n+2

To find the molecular formula, we start with n = 1, 2, 3, etc., until we find the molar mass of 44.

When n = 1

CnH2n+2 = CH4 = 12 + (4x1) = 16g/mol

When n = 2

CnH2n+2 = C2H6 = (12x2) + (6x1) = 30g/mol

When n = 3

CnH2n+2 = C3H8 = (12x3) + (8x1) = 44g/mol

It can be observed that for n equal to 3, the molar mass is 44g/mol.

Thus, the molecular formula of the alkane is C3H8.

Answer:

To prevent nested conditionals, one can utilize logical expressions like the AND operator.

A recommended approach is creating an interface class with a method designed for a shared function. This design approach is known as the strategy design pattern. The conditional statements can be consolidated into this method. Subsequently, each class can implement this interface and invoke that shared method as needed by constructing instances of subclasses and calling the common method for those objects. This illustrates polymorphism.

Explanation:

Nested conditionals occur when if or else if statements are placed within another condition. For instance:

if( condition1) {

//runs when condition1 is true

  if(condition2) {

//runs when both condition1 and condition2 are true

  }  else if(condition3) {

 //when condition1 is true and condition3 is also true

} else {

 //condition1 is true but neither condition2 nor conditions3 are satisfied

}  }

Excessive nested conditionals can complicate the program, rendering it hard to read or comprehend, particularly if there's improper indentation. Debugging also becomes challenging when there are numerous nested statements.

Thus, several strategies can be adopted to eliminate nested conditionals, such as utilizing a switch statement.

For instance, I’ll present an example of the strategies discussed earlier:

Logical Expressions Usage:

A method to avoid nested conditionals is by employing logical expressions with logical operators like the AND operator. The previous nested conditionals can be reframed as:

if(condition1 && condition2){ //only runs when both condition1 and condition2 are true

} else if(condition1 && condition3) {

executes only if both condition1 and condition3 are true

} else if(condition1 ){

//condition1 is satisfied but neither condtion2 nor condtion3 are true  }

This can be further simplified to one condition as:

if(!condition3){

// when  condition1 and condition2 are both satisfied

}

else

// condition3 is met

Now, consider a simple instance dealing with whether to attend school based on certain conditions.

if (temperature< 40)

{

   if (busArrived=="yes")

   {

       if (!sick)

       {

           if (homework=="done")

           {

               printf("Go to school.");

           }

       }                    

   }

}

Here, nested conditionals are evident. This can be restructured into a solitary conditional using the AND logical operator.

if ((temperature <40) && (busArrived=="yes") &&

(!sick) && (homework=="done"))

{    cout<<"Eligible for promotion."; }

The alternate method is utilizing an interface. For example, you can

abstract class Shape{

//declare a method common to all sub classes

  abstract public int area();

// same method that varies by formula of area for different shapes

}

class Triangle extends Shape{

  public int area() {

     // implementation of area code for Triangle

return (width * height / 2);

  }

}

class Rectangle extends Shape{

  public int area() {

     // implementation of area code for Rectangle

    return (width * height)

  }

}

Now, you can readily create Rectangle or Triangle instances and invoke area() for any of those objects, resulting in execution of the appropriate version accordingly.

The code relevant to the problem in question:

import java.util.Scanner;

public class Test {

   public static void main(String[] args) {

       double number;

       double squareRootOfNumber;

       String userInput = null;

       Scanner scanner = new Scanner(System.in);

       System.out.println("Please enter a number: ");

       userInput = scanner.next();

       number = Double.parseDouble(userInput);

       squareRootOfNumber = Math.sqrt(number);

       if (number < 0) {

           throw new ArithmeticException("Cannot compute the square root of a negative number");

       }

       System.out.format("The square root of the entered number is %.2f %n", squareRootOfNumber);

   }

}

The program will output:

Please enter a number:

-90

Exception in thread "main" java.lang.ArithmeticException: Cannot compute the square root of a negative number at com..ans.Test.main(Test.java:18)

Explanation:

The standard Java library function java.lang.Math.sqrt does not throw an ArithmeticException for negative arguments, hence there’s no need to enclose your code in a try/catch block.

Instead, we manually trigger ArithmeticException using the throw keyword:

throw new ArithmeticException("Cannot compute the square root of a negative number");