Which of the following is a true statement about cloud computing?

Respuesta: Te proporcioné 6 opciones de las cuales puedes elegir.

Integridad

Escalabilidad

Calidad de Servicio

Tolerancia a Fallos

Redes de Línea Eléctrica

Seguridad

The code relevant to the problem in question:

import java.util.Scanner;

public class Test {

   public static void main(String[] args) {

       double number;

       double squareRootOfNumber;

       String userInput = null;

       Scanner scanner = new Scanner(System.in);

       System.out.println("Please enter a number: ");

       userInput = scanner.next();

       number = Double.parseDouble(userInput);

       squareRootOfNumber = Math.sqrt(number);

       if (number < 0) {

           throw new ArithmeticException("Cannot compute the square root of a negative number");

       }

       System.out.format("The square root of the entered number is %.2f %n", squareRootOfNumber);

   }

}

The program will output:

Please enter a number:

-90

Exception in thread "main" java.lang.ArithmeticException: Cannot compute the square root of a negative number at com..ans.Test.main(Test.java:18)

Explanation:

The standard Java library function java.lang.Math.sqrt does not throw an ArithmeticException for negative arguments, hence there’s no need to enclose your code in a try/catch block.

Instead, we manually trigger ArithmeticException using the throw keyword:

throw new ArithmeticException("Cannot compute the square root of a negative number");

This problem is a personal reflection and cannot be solved without discussing it after the individual provides input.

Answer:

a) Transforming each character into its binary equivalent:

73:

The digits are 7 and 3

7 in binary is: 111

3 in binary is: 11

Thus

73: 0_111_0011

Likewise

F4:

F stands for 15 and its binary is: 1111

4 in binary: 100

Consequently

F4:  1_111_0100

E5:

E corresponds to 14 and its binary form is: 1110

5 in binary: 101

Therefore

E5:  1_110_0101

76:

7 in binary: 111

6 in binary: 110

Hence

76:  0_111_0110

E5:

E has a binary representation of: 1110

5 in binary: 101

Consequently

E5:  1_110_0101

4A:

4 in binary: 100

A represents 10

A in binary form: 1010

Therefore

4A:  0_100_1010

EF:

E in binary is: 1110

F in binary is: 1111

Thus

EF: 1_110_1111

62:

6 in binary form: 110

2 in binary form: 10

Therefore

62:  0_110_0010

73:

The digits are 7 and 3

7 in binary is: 111

3 in binary is: 11

Thus

73: 0_111_0011

for 0_1110011: the decimal equivalent is: 115 which translates to s

for 1_1110100:  the decimal equivalent is: 116 which translates to t

for 1_1100101:  the decimal equivalent is: 101 which translates to e

for 0_1110110: the decimal equivalent is:  118 which translates to v

for 1_1100101:  the decimal equivalent is: 101 which translates to e

for 0_1001010: the decimal equivalent is:  74 which translates to j

for 1_1101111: the decimal equivalent is: 111 which translates to o

for 0_1100010:  the decimal equivalent is: 98 which translates to b

for 0_1110011: the decimal equivalent is:  115 which translates to s

Thus the decoded sequence is:  stevejobs

b) The parity being utilized is odd.

for 0_1110011:  There are 5 instances of 1s and the parity is 0 indicating it is odd.

for 1_1110100: There are 4 instances of 1s and the parity is 1 indicating it is odd.

Thus, we count the number of 1s and then verify if the parity is odd or even.

Likewise

for 1_1100101:  the parity is odd

for 0_1110110: the parity is odd

for 1_1100101:  the parity is odd

for 0_1001010: the parity is odd

for 1_1101111: the parity is odd

for 0_1100010: the parity is odd

for 0_1110011: the parity is odd

Therefore, the parity being used is odd.