Uzupełnij zdania właściwymi sformułowaniami. Wyobraź sobie, że między linę a siodełko karuzeli łańcuchowej wmontowany jest siłom

Answer:

11109.825 N

Explanation:

Provided Information:

mass = m = 1510 kg

initial acceleration (a) = 0.75g (where g = 9.81 m/s²)

Using the formula F=ma

  = (1510)*(0.75*9.81)

  = 11109.825 N

This initial stage represents a right triangle. If the aircraft is positioned 400 km to the east and 300 km to the south of the origin while traveling in a straight path, you can form a right triangle with sides measuring 300, 400, and c. You might notice that these dimensions correspond to multiples of the Pythagorean triple 3, 4, 5, meaning that the length of c is 500 km. Alternatively, you would indicate
.

For the second step, assuming I am correctly understanding "degrees south of east," it involves calculating the angle between the horizontal line indicating east and the trajectory of the aircraft. I created a diagram illustrating this (see attached). You could employ a trigonometric function related to one of the angles to find the solution. I selected
. Therefore, I deduce that the angle is 37° south of east.

Answer: Known facts are:

Sadie, the dam, is a black Labrador.

Sam, the potential sire, is a yellow Labrador.

Putting aside technical methods, the breeder can inspect the puppies for traits.

For instance, yellow coat color is recessive to black, so yellow pups would suggest Sam is likely the father; however black pups could also have Sam as sire if they inherited the mother's color alleles.

Examining coat color, conformation, and similar features is a reasonable starting point.

Ultimately these observations are probabilistic; the only definitive (scientific) method is a paternity (DNA) test.

Response:

 y_red / y_blue = 1.11

Clarification:

To determine the image for each wavelength, we'll utilize the lens maker's equation

         1 /f = 1 /o + 1 /i

Where f signifies the focal length, o represents the object distance, and i indicates the image distance

For red light

           1 / i = 1 / f - 1 / o

           1 / i_red = 1 / f_red - 1 / o

           1 / i_red = 1 / 19.57 - 1/30

           1 / i_red = 1.776 10-2

           i_red = 56.29 cm

For blue light

            1 / i_blue = 1 / f_blue - 1 / o

            1 / i_blue = 1 / 18.87 - 1/30

            1 / i_blue = 1.966 10-2

            i_blue = 50.863 cm

Next, we will compute the magnification ratio

             m = y ’/ h = - i / o

             y ’= - h i / o

For red light

            y_red ’= - 5 56.29 / 30

            y_red ’= - 9.3816 cm

For blue light

            y_blue ’= 5 50.863 / 30

            y_blue ’= - 8.47716 cm

The ratio of the heights of both images is

            y_red ’/ y_blue’ = 9.3816 / 8.47716

            y_red / y_blue = 1.107

            y_red / y_blue = 1.11