In a given city, the permissible limit of CO (carbon monoxide) in the air is 100 parts per million (ppm). The city monitors the

V - wind speed;
53° - 35° = 18°
v² = 55² + 40² - 2 · 55 · 40 · cos 18°
v² = 3025 + 1600 - 2 · 55 · 40 · 0.951
v² = 440.6
v = √440.6
v = 20.99 ≈ 21 m/s
Conclusion: The wind speed calculates to 21 m/s.  

Answer:

Explanation:

Density is defined as d=m/v.

To find mass, the formula transforms into:

m=d*v

m=2700*54.3

m=146610

m=14.6*10^4

Response:

x = 1.63 m

Details:

mass (m) = 10 kg

μk = 0.3

velocity (v) = 3.1 m/s

Assuming that the weight of the computer is largely applied to the belt instantaneously, we can implement the constant acceleration equation below

x =

where a = μk.g, thus

x = /2μk.g

x = (3.1 x 3.1)/(2 x 0.3 x 9.8)

x = 1.63 m

Answer:

The distance measures

Explanation:

According to the problem statement,

The box's width is

There is a gap of length

The first spring's natural length is

The spring constant for the first spring is

The second spring has a natural length of

The second spring's spring constant is

We denote the distance from the center of the box to the left edge as x.

At equilibrium,

The force exerted by the first spring is

while the force from the second spring is

Thus, at equilibrium,

Substituting values gives us

which leads to

resulting in

and finally,

this simplifies to

The result is 28.1 mph. The friction force exerted on the car contributes the needed centripetal force that maintains the car in its circular path. We represent this with the equation: (1). The variables involved include the coefficient of friction, m the mass of the car, g = 9.8 m/s² for gravity acceleration, v for maximum speed, and r as the curve radius. For the curve on a snowy day, where the friction coefficient is at 0.50, the maximum speed recorded was 20 mph. Using that value, we can rearrange our equation to uncover the maximum speed for a sunny day at μs = 1.0, revealing the answer.