Answer:
Δx=(v+v0/2)t
Explanation:
We can determine which kinematic equation to apply by selecting the one that encompasses the known variables as well as the unknown we aim to solve for.
In this scenario, the unknown we wish to determine is the initial velocity v_0v
0
v, start subscript, 0, end subscript of the roller coaster.
The rate at which the electric field changes magnitude is derived from the given inputs. The cylindrical region has a radius of 1.2 m and is associated with a consistent electric field along the cylinder's axis. To find the rate of change of the electric field, a specific formula is utilized. Therefore, the calculated rate of electric field change is derived.
Answer:
The distance measures 
Explanation:
According to the problem statement,
The box's width is
There is a gap of length 
The first spring's natural length is 
The spring constant for the first spring is 
The second spring has a natural length of 
The second spring's spring constant is 
We denote the distance from the center of the box to the left edge as x.
At equilibrium,
The force exerted by the first spring is

while the force from the second spring is
![F_2 = k_2 * [ 0.9 - (0.9 -x)]](https://tex.z-dn.net/?f=F_2%20%3D%20%20k_2%20%2A%20%5B%200.9%20-%20%280.9%20-x%29%5D)
Thus, at equilibrium,

Substituting values gives us
![k_1 * (0.8 -x) = k_2 * [ 0.9 - (0.9 -x)]](https://tex.z-dn.net/?f=k_1%20%2A%20%280.8%20-x%29%20%3D%20%20%20%20k_2%20%2A%20%5B%200.9%20-%20%280.9%20-x%29%5D)
which leads to
![200 * (0.8 -x) = 350 * [ 0.9 - (0.9 -x)]](https://tex.z-dn.net/?f=200%20%2A%20%280.8%20-x%29%20%3D%20%20%20%20350%20%2A%20%5B%200.9%20-%20%280.9%20-x%29%5D)
resulting in

and finally,

this simplifies to
