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frozen
5 days ago
10

Each histogram represents a set of data with a median of 29.5. Which set of data most likely has a mean that is closest to 29.5?

Mathematics
2 answers:
zzz [12.3K]5 days ago
6 0

Answer:

B

Detailed explanation:

AnnZ [12.3K]5 days ago
5 0

Answer:

Refer to the figure attached.

Detailed explanation:

Here are several pointers for relating the histogram to the mean and median.

1) In cases where the histogram shows a right skew, the mean exceeds the median.

2) When the histogram nearly resembles a symmetrical shape, the mean and median will be relatively similar.

3) In situations where the histogram is skewed to the left, the mean will fall below the median.

Thus, based on the provided data, the median is 29.5, and the mean approximates this value.

Consequently, it indicates that the histogram is nearly symmetric.

Therefore, the data set that probably has a mean closest to 29.5 is represented in the accompanying figure.

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Mookie Betts of the Boston Red Sox had the highest batting average for the 2018 Major League Baseball season. His average was 0.
Leona [12618]

Answer:

Binomial probability, with n = 5, p = 0.352

Step-by-step explanation:

Each time Mookie Betts stepped up to bat, there were only two possible results: either he achieved a base hit or he didn't. The odds of hitting during each at-bat remain unaffected by prior attempts. Therefore, the binomial probability distribution applies to tackle this problem.

Binomial probability distribution

The chance of getting exactly x successes over n trials, considering p probability.

His batting average stood at 0.352.

This indicates that p = 0.352

Let's assume he bats five times in tonight's matchup against the Yankees.

This means that n = 5

a. This showcases what type of probability

Binomial probability, with n = 5, p = 0.352

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16 days ago
Becca hikes 9/10 mile in 3/5 hour. Which fraction represents Becca's speed in miles per hour? The answer choices are: 3/5 / 9/10
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Response:9/10/3/5

Detailed explanation: because... believe me

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a speed limit of 100 kilometers per hour is approximately equal to 62 miles per hour. write an equation relating kilometers per
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The conversion between these units is 1 km/hr = 0.62 m/hr
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At a recent county fair, you observed that at one stand people's weight was forecasted, and were surprised by the accuracy (with
Leona [12618]

Answer:

a) Slope: \hat \beta_1 =\frac{7625.9}{1248.9}=6.106

Intercept: \hat \beta_o = 157.955 -6.106 (69.686)=-267.548

b) r=\frac{7625.9}{\sqrt{[1248.9][94228.8]}}=0.657

Additionally, the coefficient of determination is r^2 = 0.657^2 =0.432

Step-by-step explanation:

Definitions and data provided

The correlation coefficient is a measure that quantifies the strength of the relationship between two variable movements, denoted as r and ranging between -1 and 1.

The sum of squares refers to the total of the squared deviations, where deviation is defined as the difference between each value and the grand mean.

When performing multiple regression, the aim is to analyze the relationship between multiple independent variables and one dependent variable.

n=110, \sum x_i y_i = \sum (X-\bar X)(Y-\bar Y) =7625.9,\sum x^2_i=\sum (x-\bar x)^2 =1248.9, sum y^2_i=\sum(y-\bar y)^2 =94228.8

\sum Y_i =17375, \sum X_i = 7665.5

Part a

The slope can be calculated using this formula:

\hat \beta_1 =\frac{\sum (x-\bar x) (y-\bar y)}{\sum (x-\bar x )^2}

Following the substitutions, we have:

\hat \beta_1 =\frac{7625.9}{1248.9}=6.106

The intercept can be determined with this formula:

\hat \beta_o = \bar y -\hat \beta_1 \bar x

Average values for x and y can be calculated this way:

\bar X=7665.5/110 =69.686, \bar y= 17375/110=157.955

Replacing yields:

\hat \beta_o = 157.955 -6.106 (69.686)=-267.548

Part b

The correlation coefficient can be calculated using the following formula:

r=\frac{\sum (x-\bar x)(y-\bar y) }{\sqrt{[\sum (x-\bar x)^2][\sum(y-\bar y)^2]}}

In our situation:

n=110, \sum x_i y_i = \sum (X-\bar X)(Y-\bar Y) =7625.9,\sum x^2_i=\sum (x-\bar x)^2 =1248.9, sum y^2_i=\sum(y-\bar y)^2 =94228.8

We can compute the correlation coefficient by substituting values:

r=\frac{7625.9}{\sqrt{[1248.9][94228.8]}}=0.657

The coefficient of determination is r^2 = 0.657^2 =0.432

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