The required duration is 16.1 minutes. To determine the heat needed to raise the temperature, we must calculate the following amounts, where Q represents the required heat, m stands for mass, V represents the volume, C signifies specific heat, and ΔT indicates temperature change. After substituting the provided values into the formula and calculating, the next step is determining the required time based on the formula t = Q/P, where P is given as 1500 W. Ultimately, we find that the time needed is 16.1 minutes.
Answer:
The surface area of the dog changes from A to 3A
Explanation:
It is stated that the dog's surface area has increased by a factor of 3 over four years.
We need to calculate the change in the relative surface area of the dog over this timeframe.
Let’s assume the initial surface area is A.
Since the surface area has been multiplied by 3,
it follows that the surface area after four years is equal to 3×A = 3A.
Thus, the dog's surface area transitions from A to 3A.
Response:
Clarification:
The force between two charges, q₁ and q₂ at a distance d is represented by the formula
F = k q₁ q₂ / d²
Here, the force between charge q₁ = -15 x 10⁻⁹ C and q₃ = 47 x 10⁻⁹ C with distance d = (1.66 - 1.24) = 0.42 mm
k = 1 / (4π x 8.85 x 10⁻¹²)
Substituting the values into the equation
F = 1 / (4π x 8.85 x 10⁻¹²) x -15 x 10⁻⁹ x 47 x 10⁻⁹ / (0.42 x 10⁻³)²
= 9 x 10⁹ x -15 x 10⁻⁹ x 47 x 10⁻⁹ / (0.42 x 10⁻³)²
= 35969.4 x 10⁻³ N.
For the force between charge q₂ = 34.5 x 10⁻⁹ C and q₃ = 47 x 10⁻⁹ C at a distance d = (1.24 - 0) = 1.24 mm.
Substituting the values into the expression
F = 1 / (4π x 8.85 x 10⁻¹²) x 34.5 x 10⁻⁹ x 47 x 10⁻⁹ / (0.42 x 10⁻³)²
= 9 x 10⁹ x -34.5 x 10⁻⁹ x 47 x 10⁻⁹ / (0.42 x 10⁻³)²
= 82729.6 x 10⁻³ N
Both forces direct towards the left (away from the origin, towards the negative x-axis)
Total force = 118699 x 10⁻³
= 118.7 N.
Answer:
1.5 × 10³⁶ light-years
Explanation:
A particular square area in interstellar space measures roughly 2.4 × 10⁷² (light-years)². To find the area of a square, the following formula is utilized:
A = l²
where,
A represents the area of the square
l denotes the length of one side of the square
Thus, l = √A = √2.4 × 10⁷² (light-years)² = 1.5 × 10³⁶ light-years
Answer:
option D.
Explanation:
The correct choice is option D.
For an object in equilibrium, the torque measured at any point will be zero.
An object is deemed to be in equilibrium when the net moment acting on it equals zero.
If the object experiences a net moment not equal to zero, it will rotate and will not remain stable.
