A 15.0-Ω resistor and a coil are connected in series with a 6.30-V battery with negligible internal resistance and a closed swit

<span>θ=0.3sin(4t)
w=0.3cos(4t)(4)=1.2cos(4t)
a=-4.8sin(4t)

Knowing that the maximum of cos4t is always 1 (as seen in the cosine graph), similarly, sin4t will always equal 0

Thus, the maximum rate of w = 1.2 rad/s
 
vAmax=r*w=250*1.2=300 mm/s
(may vary if your graph/radius is derived from a different source)

adt=a*r=200*-4.8sin(4t)=0 (when sin(4t)=0)

adn=r*w^2=200*1.2^2=288

ad= the square root of adt^2 + adn^2 = 288 mm/s^2</span>

Response:

v = 4.08 m/s²

Clarification:

Answer

Given:

Wavelength = λ = 18.7 cm

                  = 0.187 m

Amplitude, A = 2.34 cm

Velocity, v = 0.38 m/s

A)  Calculate the angular frequency.

     

     

     

Angular frequency,

ω = 2π f

ω = 2π x 2.03

ω = 12.75 rad/s

B) Calculate the wave number:

     

     

   

C)

Since the wave is traveling in the -x direction, the sign is positive between x and t

y (x, t) = A sin(k x - ω t)

y (x, t) = 2.34 sin(33.59 x - 12.75 t)