The force exerted by the car on the bug is identical to the force the bug applies back on the car.
275 kPa Explanation: Here the mass of the gas equals m=1.5 kg with an initial volume of V₁=0.04 m³ and an initial pressure P₁=550 kPa. As provided, the final volume is double the original volume, making V₂ equal to 2 V₁. Since the temperature remains constant, T₁=T₂=T. By substituting the values into the equation... results in final pressure being P₂=275 kPa.
At time 
, the ball's horizontal and vertical velocities can be represented as
However, since the ball is thrown horizontally, we have 
. The horizontal and vertical positions at time are
The ball travels a distance of 22 m horizontally from the throw point, thus
With this, we determine that the time for the ball to reach the ground is
When it touches down, 
and
Result: 168N
The calculation shows 16 - 10 equals 6
and 6 divided by 10 equals 0.6
. Therefore, F equals 280 multiplied by 0.6 equals 168.
