Two objects are placed in thermal contact and are allowed to come to equilibrium in isolation. The heat capacity of Object A is

Question

3 months ago

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Two objects are placed in thermal contact and are allowed to come to equilibrium in isolation. The heat capacity of Object A is

three times the heat capacity of Object B and the initial temperature of Object A (TA) is twice the initial temperature of Object B (TB).
1)

What will the final temperature of the two-object system be?

2TB

1.75TB

1.5TB

1.2TB

TB

Physics

1 answer:

kicyunya [3.2K] · Answer 1 · 2026-03-20T00:27:46+03:00

Heat capacity of A is three times that of B

and the initial temperature for A is twice that of B

with TA = 2 TB

Let T denote the final temperature of the system.

The heat lost by A equals the heat gained by B:

mass of A x specific heat of A x (TA - T) = mass of B x specific heat of B x ( T - TB)

which simplifies to heat capacity of A x ( TA - T) = heat capacity of B x ( T - TB)

resulting in 3 x heat capacity of B x ( TA - T) = heat capacity of B x ( T - TB).

This leads us to the equation: 3 TA - 3 T = T - TB

which rearranges to yield 6 TB + TB = 4 T

thus giving us T = 1.75 TB