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zysi
3 months ago
12

Two of the types of ultraviolet light, uva and uvb, are both components of sunlight. their wavelengths range from 320 to 400 nm

for uva and from 290 to 320 nm for uvb. compare the energy of microwaves, uva, and uvb. rank from greatest to least energy per photon. to rank items as equivalent, overlap them.
Physics
2 answers:
Sav [3.1K]3 months ago
7 0

In terms of light energy, a higher frequency corresponds to increased energy within the light.

We establish that frequency is essentially the inverse of wavelength:

frequency = 1 / wavelength

Calculating frequencies:

f UVA = 1/320 to 1/400

f UVA = 0.0031 to 0.0025

 

f UVB = 1/290 to 1/320

f UVB = 0.0034 to 0.0031

Since UVB occupies a higher frequency range, it consequently possesses greater energy than UVA.

ValentinkaMS [3.4K]3 months ago
3 0

Response:

uvb > uva > microwaves

Justification:

The energy associated with an electromagnetic wave is given by

E =\frac{hc}{\lambda}

Where

h represents Planck's constant

c signifies the speed of light and

\lambda is the frequency

This helps us conclude that energy is inversely related to wavelength

The wavelength ranges are as follows:

1. microwaves - 1 mm - 1m

2. uva - 320 - 400 nm

3. uvb - 290 - 320 nm

Consequently, due to its shorter wavelength, uvb is the form possessing the highest energy, while microwaves, with their larger wavelength range, exhibit the least energy; thus, the conclusion is uvb > uva > microwaves

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