Two parallel plates of area 2.34*10-3 M2 have 7.07*10-7C of charge placed on them. A6.62*10-5C charge q1 is placed between the p

D) Both perform no work

Explanation:

The work accomplished by a force is defined as:

where

F represents the applied force

d denotes the displacement

is the angle highlighted between the applied force and the displacement vector

From this formula, it is clear that work is only done when displacement occurs, meaning the object has to move.

In this instance, as the wall is unmoving, the displacement is zero: d = 0, thus no work is performed.

<span>The partial pressure of A = 1.06 atm and the partial pressure of B = 0.53 atm</span>

Answer:

Explanation:

To approach this problem, we need to understand two key concepts.

First, the gravitational force on an object in orbit equals its mass multiplied by centripetal acceleration.

Secondly, Newton's law of universal gravitation defines the force between two masses: Fg = mMG/r², where Fg denotes gravitational force, m and M signify the masses, G represents the gravitational constant, and r indicates the distance separating the two masses.

Thus:

Fg = m v²/r

mMG/r² = m v²/r

v² = MG/r

Potential energy for each planet is expressed as:

PE = mgr = m (MG/r²) r = mMG/r

Kinetic energy for each planet is computed as:

KE = 1/2 mv² = 1/2 m (MG/r) = 1/2 mMG/r

Total mechanical energy is calculated as:

ME = PE + KE = 3/2 mMG/r

Since both planets share the same mass, the only variable is their orbital radius. Consequently, Planet A, with a smaller radius, possesses greater potential, kinetic, and mechanical energy.

Answer:

Explanation:

The four wires are arranged in series: this setup indicates that the same current passes through them, while the total voltage from the battery, V0, equals the combined voltages across each resistor:

Additionally, the total resistance for this series configuration is

Using Ohm's law, we can determine the voltage V2 across wire 2:

(1)

Here, I represents the entire current flowing through the circuit, which is calculated as:

By substituting into equation (1), we derive V2:

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