A responder can protect himself/herself from radiation by using shielding as a response action. What materials are best for prot

mass₃<mass₁=mass₅<mass₂=mass₄

Explanation:

Data points:-

1. mass:  m      speed: v

2. mass: 4 m   speed: v

3. mass: 2 m   speed: ¼ v

4. mass: 4 m   speed: v

5. mass: 4 m   speed: ½ v

We know that the formula for Kinetic energy (KE) is ½ mv²

Where m represents the mass of the object

           v represents the object's velocity

The KE of Body 1(mass₁) = ½*m*v²             = mv²/2

KE of Body 2(mass₂) = ½*4m*v²         = 2mv²

KE of Body 3(mass₃) = ½*2m*(1/4v)²  =  mv²/16

KE of Body 4(mass₄) = ½*4m*v ²        =  2mv ²

KE of Body 5(mass₅) = ½*4m*(1/2v)²  =   mv²/2

Response:

The population mean is parameter = 65 c

Explanation:

In the analysis of samples and inferring population behavior, two key elements are essential.

To ascertain the population mean, we typically extract various samples and calculate their average. The average of all these means will serve as an estimate for the population mean. According to the central limit theorem, as sample sizes increase, the average of a sample tends to follow a normal distribution with an estimated mean being the sample mean.

A statistic pertains to a sample, while a parameter refers to the whole population.

In this case, 65 degrees C represents the entire population; thus, it constitutes a parameter.

To find the volume, we can utilize the ratio of mass to density, as shown by:

volume = mass / density

A. when mass = 5.5 kg = 5500 g; density = 1.60 g/cm^3

volume = 5500 g / (1.60 g/cm^3)

resulting in volume = 3,437.5 cm^3

By rounding according to significant digits:

volume = 3,400 cm^3 = 3.4 L

B. when mass = 4.9 kg = 4900 g; density = 1.36 g/cm^3

volume = 4900 g / (1.36 g/cm^3)

calculating gives volume = 3,602.94 cm^3

Considering significant digits:

<span>volume = 3,600 cm^3 = 3.6 L</span>

Answer:

The correct option is 80 dB.

Explanation:

The transformation of sound intensity level into sound intensity utilizes the formula

[D] = 10 log (I/I₀)

Where I₀ = 10⁻¹² W/m²

[D] results in 100 dB

100 = 10 log (I/I₀)

Log (I/I₀) converts to 10

(I/I₀) = 10¹⁰

I is determined as I₀ × 10¹⁰ = 10⁻¹² × 10¹⁰ = 10⁻² W/m²

Sound intensity inversely relates to the square of the distance from the source.

I ∝ (1/d²)

I can be expressed as k/d²

When d = 1 m, the intensity is 10⁻² W/m²

Thus, 0.01 = k/1

Providing that k = 0.01 W

For d = 20 m, we can calculate I

I = 0.01/20² = 2.5 × 10⁻⁵ W/m²

With four neighbors mowing their lawns concurrently,

I = 4 × 2.5 × 10⁻⁵ = 10⁻⁴ W/m⁻²

The sound intensity level in decibels is represented as

[D] = 10 log (I/I₀)

[D] = 10 log (10⁻⁴/10⁻¹²)

[D] = 10 log (10⁸)

[D] = 10 × 8 = 80dB

Response:

Clarification:

If

• , represent the temperatures of gases and liquids in Kelvins,

• and denote the thicknesses of the gas layer and steel slab in meters,
• , are the convection coefficients for gas and liquid in ,
• represents the contact resistance in ,

• and signify thermal conductivities of gas and steel in ,

then: part(a):

by employing known values:

part(b): Utilizing the rate equation:

the surface temperature is

and

Correspondingly

The temperature profile is depicted in the image provided