Answer
Given:
Wavelength = λ = 18.7 cm
= 0.187 m
Amplitude, A = 2.34 cm
Velocity, v = 0.38 m/s
A) Calculate the angular frequency.
Angular frequency,
ω = 2π f
ω = 2π x 2.03
ω = 12.75 rad/s
B) Calculate the wave number:
C)
Since the wave is traveling in the -x direction, the sign is positive between x and t
y (x, t) = A sin(k x - ω t)
y (x, t) = 2.34 sin(33.59 x - 12.75 t)
Answer:
σ₁ = C/m²
σ₂ = C/m²
Explanation:
Provided Information:
i) Smaller sphere's radius ( r ) = 5 cm.
ii) Larger sphere's radius ( R ) = 12 cm.
iii) Electric field at the larger sphere's surface ( E₁ ) = 358 kV/m, which is equivalent to 358 * 1000 v/m
Charge (Q₁) = 572.8 C
Since the electric field inside a conductor is zero, the electric potential ( V ) remains constant.
V = constant
∴
=
C
Surface charge density ( σ₁ ) for the larger sphere.
Calculated Area ( A₁ ) = 4 * π * R² = 4 * 3.14 * 0.12 = 0.180864 m².
σ₁ = =
=
C/m².
Surface charge density ( σ₂ ) for the smaller sphere.
Calculated Area ( A₂ ) = 4 * π * r² = 4 * 3.14 * 0.05² = 0.0314 m².
σ₂ = =
=
C/m²
Answer:
Explanation:
To begin with, we must determine the pressure acting on the sphere, which is calculated using:
where
denotes the atmospheric pressure
represents the density of the water
signifies the acceleration due to gravity
indicates the depth
By substituting these values,
The sphere's radius is calculated as r = d/2 = 1.1 m/2 = 0.55 m
Thus, the sphere's total surface area can be expressed as
Consequently, the inward force acting on the sphere equals