What is the inverse of the function f(x) = one-quarterx – 12? h(x) = 48x – 4 h(x) = 48x + 4 h(x) = 4x – 48 h(x) = 4x + 48

2 answers:

8 0

h(x) = 4x + 48. Explanation: To find the inverse of the function f(x) = 1/4x - 12, first set y = f(x), solve for x, and after isolating the variable, the inverse can be expressed as h(x).

Zina [12.3K]1 month ago

4 0

The inverse function is defined as h(x) = 4x + 48. To derive it from f(x) = 1/4x - 12, substitute y = f(x) and rearrange the equation to isolate x as shown, leading to h(x).

You might be interested in

Suppose we are given 4 sets A, B, C, D such that A ⊆ B and C ⊆ D such that A and C have no elements in common. Prove or give a c

babunello [11817]

Here’s a counterexample: consider

$B = \{1, 2, 3, 4, 5\},\quad D = \{A, B, C, D, 5\}$

Select the subsets in the following manner:

$A = \{1, 5\},\quad C = \{A, B, C\}$

It's accurate that $A\subseteq B$ and $C\subseteq D$ and that $A\cap C=\emptyset$ , but $A\cap D = \{5\}$

8 0

2 months ago

A common inhabitant of human intestines is the bacterium Escherichia coli, named after the German pediatrician Theodor Escherich

babunello [11817]

A.) P(t) = P0e^(kt)
P(20/60) = 40 e^(20k/60)
80 = 40 e^(k/3)
e^(k/3) = 80/40 = 2
k/3 = ln(2)
k = 3ln(2)

b.) P(8) = 40(2)^24 = 40(16777216) = 671088640 cells

d.) Rate of change = e^(8k) = e^(8(3ln(2))) = e^(24ln(2)) = e^(16.6355) = 16777216 cells/hour

e.) P(t) = 40(2)^(3t); t in hours
1,000,000 = 40(8)^t
25,000 = 8^t
ln(25,000) = t ln(8)
t = ln(25,000)/ln(8) = 4.87 hours

8 0

2 months ago

Read 2 more answers