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zavuch27
5 days ago
5

A customer/member owes $11.02 and pays $100.00 in cash. The change due is $88.98. Provide the amount owed using the smallest num

ber of bills and coins possible.
Mathematics
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Given: KL ║ NM , LM = 45, m∠M = 50° KN ⊥ NM , NL ⊥ LM Find: KN and KL
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Answer:

KL=45\tan 50^{\circ}\sin 50^{\circ}\approx 41.08\\ \\KN=45\sin 50^{\circ}\approx 34.47

Step-by-step explanation:

Given:

KL ║ NM,

LM = 45

m∠M = 50°

KN ⊥ NM  

NL ⊥ LM

To determine: KN and KL

1. Analyzing triangle NLM, we see it is a right triangle due to NL ⊥ LM. In this context,

LM = 45

m∠M = 50°

Consequently,

\tan \angle M=\dfrac{\text{opposite leg}}{\text{adjacent leg}}=\dfrac{NL}{LM}=\dfrac{NL}{45}\\ \\NL=45\tan 50^{\circ}

It is also true that

(angles LNM and M are complementary).m\angle LNM=90^{\circ}-50^{\circ}=40^{\circ}

2. Now considering triangle NKL, it also forms a right triangle as KN ⊥ NM. Within this triangle,

NL=45\tan 50^{\circ}

m\angle KLN=m\angle LNM=40^{\circ} (alternate interior angles)

m\angle KNL=90^{\circ}-40^{\circ}=50^{\circ} (angles KNL and KLN are complementary).

Thus,

\sin \angle KNL=\dfrac{\text{opposite leg}}{\text{hypotenuse}}=\dfrac{KL}{LN}=\dfrac{KL}{45\tan 50^{\circ}}\\ \\KL=45\tan 50^{\circ}\sin 50^{\circ}\approx 41.08

and

\cos \angle KNL=\dfrac{\text{adjacent leg}}{\text{hypotenuse}}=\dfrac{KN}{LN}=\dfrac{KN}{45\tan 50^{\circ}}\\ \\KN=45\tan 50^{\circ}\cos 50^{\circ}=45\sin 50^{\circ}\approx 34.47

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Martin is cleaning all the rooms in his house. There are 4 rooms left to clean, and he takes 7 hours to clean them. Write the eq
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Consequently, the equation determining the remaining number of rooms Martin has to clean after hours can be represented as:

y=-\frac{4}{7}x+b

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y=-\frac{4}{7}x+b (Answer)

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