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Marina86
7 days ago
10

Find the value of x in each case

Mathematics
1 answer:
PIT_PIT [12.4K]7 days ago
6 0
When x is encountered, don't look back; don't be weak.
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lawyer [12517]

Answer:

143, I believe

Step-by-step explanation:

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1 month ago
Given: mTRV = 60° mTRS = (4x)° Prove: x = 30 What is the missing reason in step 3? substitution property of equality angle addit
tester [12383]
The reason is rooted in the angle addition postulate. If we have the scenario where TR is a line intersecting segment VS at point R, we can establish that by applying the angle addition postulate, we can deduce that x is equal to 30. In option (1), which uses the substitution property of equality, this condition cannot be utilized correctly here. Option (3) involving the subtraction property of equality does not apply either. Lastly, option (4) regarding the addition property of equality is also inappropriate for deriving the value of x.
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14 days ago
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If (a^3+27)=(a+3)(a^2+ma+9) then m equals
Inessa [12570]

Answer:

m = - 3

Step-by-step explanation:

a³ + 27 can be recognized as a sum of cubes, which factors generally as

a³ + b³ = (a + b)(a² - ab + b²). Therefore:

a³ + 27

= a³ + 3³

= (a + 3)(a² - 3a + 9).

By comparing a² - 3a + 9 to a² + ma + 9, we find that

m = - 3.

7 0
1 month ago
Suppose you have two urns with poker chips in them. Urn I contains two red chips and four white chips. Urn II contains three red
Zina [12379]
There are several possible outcomes. The initial composition of the urns is as follows: Urn 1 contains 2 red chips and 4 white chips, totaling 6 chips, whereas Urn 2 has 3 red and 1 white, amounting to 4 chips. When a chip is drawn from the first urn, the probabilities are as follows: for a red chip, it is probability is (2 red from 6 chips = 2/6 = 1/2); for a white chip, it is (4 white from 6 chips = 4/6 = 2/3). After the chip is transferred to the second urn, two scenarios can arise: if the chip drawn from the first urn is white, then Urn 2 will contain 3 red and 2 white chips, making a total of 5 chips, creating a 40% chance for drawing a white chip. Conversely, if a red chip is drawn first, Urn 2 will contain 4 red and 1 white chip, which results in a 20% chance of drawing a white chip. This scenario exemplifies a dependent event, as the outcome hinges on the type of chip drawn first from Urn 1. For the first scenario, the combined probability is (the probability of drawing a white chip from Urn 1) multiplied by (the probability of drawing a white chip from Urn 2), equaling 26.66%. For the second scenario, the probabilities yield a value of 6%.
8 0
1 month ago
Moesha and Keyon are mailing invitations for their wedding. They have $50 to spend and each invitation costs $1.25 to mail. The
zzz [12365]

Answer:

The solution to the equation is 40

This indicates the max number of wedding invitations they can afford to send within their budget.

Step-by-step explanation:

To find the zero of the function, we set the dependent variable (here, m) to zero.

So we have;

0 = 50-1.25w

1.25w = 50

w = 50/1.25

w = 40

What implication does this have in this context?

Essentially, it means that the couple can send out invitations to a total of 40 people based on their budget.

7 0
1 month ago
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