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olya-2409
1 month ago
5

A student prepares a solution by combining 100 mL of 0.30 M HNO2(aq) and 100 mL of 0.30 M KNO2(a). Which of the following equati

ons represents the reaction that best helps to explain why adding a few drops of 1.0 M HCI(aą) does not significantly change the pH of the solution? (A) K*(aq) + CI (aq) ---------------->KCl(s)(B) HNO2(aą) ----------------->H'(aą) + NO2 (aq) (C) H (aq) + OH (aq) ----------------->H2O(l)
Chemistry
1 answer:
Tems11 [2.4K]1 month ago
7 0

Answer:

B

Explanation:

This combination forms a buffer solution, meaning it will effectively neutralize and not significantly alter the pH level.

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When a 3.22 g sample of an unknown hydrate of sodium sulfate, na2so4 ⋅ h2o(s), is heated, h2o (molar mass 18 g) is driven off. T
lions [2653]

Given that the value of X is 10, the formula for the unknown hydrate of sodium sulfate becomes NaSO4.10 H2O.

Calculation:

Step 1: Determine the moles of Na2SO4 and H2O.

Moles are calculated by dividing mass by molar mass.

Moles of Na2SO4 are calculated as 1.42 divided by 142, resulting in 0.01 moles.

For H2O: The mass of H2O is 3.22 - 1.42 = 1.8 g.

The moles of H2O are then calculated as 1.8 divided by 18, which gives us 0.1 moles.

Step 2: Find the mole ratio by dividing each mole quantity by the smallest amount (0.01).

This leads to Na2SO4 = 0.01/0.01 = 1.

            H2O = 0.1/0.01 = 10.

6 0
1 month ago
How many moles of ions are in 285 ml of 0.0150 m mgcl2?
Tems11 [2400]
MgCl₂)= Mg²⁺ + 2Cl⁻
V(MgCl₂)=285cm³=0,285dm³
c(MgCl₂)=0,015 mol/dm³
n(MgCl₂)=c·V= 0,015 mol/dm³ · 0,285dm³ = 0,0042 mol
n(Mg²⁺)=n(MgCl₂)=0,0042 mol
n(Cl⁻)=2n(MgCl₂)=0,0084 mol
7 0
12 days ago
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Which molecules show an appropriate number of bonds around each carbon atom? select the three that apply.the shape of molecules
Anarel [2600]
In my opinion, the best choice among the options given is that the three-dimensional form of molecules is significant. This shape depends on how covalent bonds orient themselves spatially around atoms bonded to two or more partners.
I hope my explanation helps you. Feel free to ask more questions here on Brainly.
7 0
1 month ago
How many atoms are there in 5.699 g of cobalt, Co? Express your answer with the appropriate significant figures and unit.
Anarel [2600]
There are 5.824x10^22 atoms of cobalt in 5.699 grams of cobalt. To begin, calculate the moles of cobalt by dividing the mass by its atomic weight. The atomic weight of cobalt is 58.933195 g/mol. So, the mole count for cobalt = 5.699 g / 58.933195 g/mol = 0.096702716 mol. To find the total number of atoms, multiply by Avogadro's number: 0.096702716 * 6.0221409x10^23 = 5.823574x10^22. Rounding to four significant figures gives 5.824x10^22.
6 0
12 days ago
if 2.34 moles of Tin IV Chloride reacts with 4.36 moles of sodium, according to the following reaction, what is the maximum numb
eduard [2509]

1.09 moles of tin (Sn)

Explanation:

The reaction we are examining involves tin chloride (SnCl₂) reacting with sodium (Na) to yield tin (Sn) and sodium chloride (NaCl):

SnCl₄ + 4 Na → Sn + 4 NaCl

Considering the chemical equation, this results in:

If 1 mole of SnCl₂ reacts with 4 moles of Na,

then 2.34 moles of SnCl₂ will react with X moles of Na.

X = (2.34 × 4) / 1 = 9.36 moles of Na

So, 2.34 moles of SnCl₂ can react with 9.36 moles of Na, but we have only 4.36 moles of Na on hand. Therefore, Na is the limiting reactant. Based on this, we can conclude:

If 4 moles of Na yield 1 mole of Sn,

then 4.36 moles of Na will produce Y moles of Sn.

Y = (4.36 × 1) / 4 = 1.09 moles of Sn

Learn more about:

limiting reactant

7 0
1 month ago
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