Given that the value of X is 10, the formula for the unknown hydrate of sodium sulfate becomes NaSO4.10 H2O.
Calculation:
Step 1: Determine the moles of Na2SO4 and H2O.
Moles are calculated by dividing mass by molar mass.
Moles of Na2SO4 are calculated as 1.42 divided by 142, resulting in 0.01 moles.
For H2O: The mass of H2O is 3.22 - 1.42 = 1.8 g.
The moles of H2O are then calculated as 1.8 divided by 18, which gives us 0.1 moles.
Step 2: Find the mole ratio by dividing each mole quantity by the smallest amount (0.01).
This leads to Na2SO4 = 0.01/0.01 = 1.
H2O = 0.1/0.01 = 10.
MgCl₂)= Mg²⁺ + 2Cl⁻
V(MgCl₂)=285cm³=0,285dm³
c(MgCl₂)=0,015 mol/dm³
n(MgCl₂)=c·V= 0,015 mol/dm³ · 0,285dm³ = 0,0042 mol
n(Mg²⁺)=n(MgCl₂)=0,0042 mol
n(Cl⁻)=2n(MgCl₂)=0,0084 mol
In my opinion, the best choice among the options given is that the three-dimensional form of molecules is significant. This shape depends on how covalent bonds orient themselves spatially around atoms bonded to two or more partners.
I hope my explanation helps you. Feel free to ask more questions here on Brainly.
There are 5.824x10^22 atoms of cobalt in 5.699 grams of cobalt. To begin, calculate the moles of cobalt by dividing the mass by its atomic weight. The atomic weight of cobalt is 58.933195 g/mol. So, the mole count for cobalt = 5.699 g / 58.933195 g/mol = 0.096702716 mol. To find the total number of atoms, multiply by Avogadro's number: 0.096702716 * 6.0221409x10^23 = 5.823574x10^22. Rounding to four significant figures gives 5.824x10^22.
1.09 moles of tin (Sn)
Explanation:
The reaction we are examining involves tin chloride (SnCl₂) reacting with sodium (Na) to yield tin (Sn) and sodium chloride (NaCl):
SnCl₄ + 4 Na → Sn + 4 NaCl
Considering the chemical equation, this results in:
If 1 mole of SnCl₂ reacts with 4 moles of Na,
then 2.34 moles of SnCl₂ will react with X moles of Na.
X = (2.34 × 4) / 1 = 9.36 moles of Na
So, 2.34 moles of SnCl₂ can react with 9.36 moles of Na, but we have only 4.36 moles of Na on hand. Therefore, Na is the limiting reactant. Based on this, we can conclude:
If 4 moles of Na yield 1 mole of Sn,
then 4.36 moles of Na will produce Y moles of Sn.
Y = (4.36 × 1) / 4 = 1.09 moles of Sn
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limiting reactant