How many molecules of ethane (C2H6) are present in 0.334 g of C2H6?
1 answer:
Response:
6.6253*10²¹ molecules of ethane (C₂H₆) can be found in 0.334 g of C₂H₆.
Explanation:
Avogadro's Number signifies the quantity of particles within a certain amount of a substance, typically represented as one mole. It is defined as 6.023 * 10²³ particles per mole and applies universally across substances.
In this case:
- C: 12 g/mole
- H: 1 g/mole
Thus, the molar mass for ethane C₂H₆ is:
C₂H₆: 2*12 g/mole + 6*1 g/mole= 30 g/mole
Next, utilizing a proportional calculation: if 30 grams of C₂H₆ represent 1 mole, we can determine the moles in 0.334 grams of C₂H₆.
moles of C₂H₆=0.011
Finally, observing Avogadro's number: if one mole holds 6.023 * 10²³ molecules of C₂H₆, how many are present in 0.011 moles?
molecules of C₂H₆= 6.6253*10²¹
Thus, 6.6253*10²¹ molecules of ethane (C₂H₆) are found in 0.334 g of C₂H₆.
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The new volume is:
Rationale:
Because the temperature remains constant, we can apply Boyle's Law to solve this issue.
Boyle's Law stipulates that:
Where,
P is the gas's pressure.
V is the gas's volume.
According to the information provided:
Let's put the values into the equation:
Consequently, the new volume is:
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