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2 months ago

How many moles of ions are in 285 ml of 0.0150 m mgcl2?

2 answers:

7 0

MgCl₂)= Mg²⁺ + 2Cl⁻
V(MgCl₂)=285cm³=0,285dm³
c(MgCl₂)=0,015 mol/dm³
n(MgCl₂)=c·V= 0,015 mol/dm³ · 0,285dm³ = 0,0042 mol
n(Mg²⁺)=n(MgCl₂)=0,0042 mol
n(Cl⁻)=2n(MgCl₂)=0,0084 mol

lions [2.9K]2 months ago

3 0

The quantities of $Mg^{2+}$ and $Cl^-$ ions consist of 0.00428 and 0.00856 moles, respectively. Explanation: Molarity is defined as the number of moles of solute in one liter of a solution. In this context, the solute in question is $MgCl_2$ . Given data includes: Volume of the solution = 285 mL = 0.285 L (as 1 L = 1000 mL); Molarity = 0.0150 M. Utilizing the provided values in our formula yields: The moles of $MgCl_2$ is calculated to be 0.00428 moles. According to stoichiometric relationships, 1 mole of $MgCl_2$ separates into 1 mole of $Mg^{2+}$ ions and 2 moles of $Cl^-$ ions. Therefore, the mole quantities are: Moles of $Mg^{2+}$ = 0.00428 and Moles of $Cl^-$ = 2 × 0.00428 = 0.00856. Thus, the respective mole amounts for $Mg^{2+}$ and $Cl^-$ ions are 0.00428 and 0.00856.

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Consider the following system at equilibrium:

VMariaS [2998]

Answer:

A - Increase (R), Decrease (P), Decrease(q), Triple both (Q) and (R)

B - Increase(P), Increase(q), Decrease (R)

C - Triple (P) and cut (q) down to a third

Explanation:

According to the principle of Le Chatelier, when a system reaches equilibrium and a change is introduced, the system will respond to counteract that change.

Since P and Q are reactants, raising the amount of either one or both without a proportional rise in R (which is a product) will cause the equilibrium to move towards the right. Similarly, if R decreases while P and Q remain constant, this too will push the equilibrium to the right. Thus, Increase(P), Increase(q), and Decrease(R) will lead to a rightward shift in the equilibrium.

Conversely, raising R without increasing P and Q will draw the equilibrium to the left. Likewise, cutting down P and/or Q without a similar reduction in R will shift the equilibrium leftward. Therefore, Increase(R), Decrease(P), Decrease(q), and triple both (Q) and (R) will shift the equilibrium to the left.

If there are equivalent changes in P and Q, with R remaining unchanged, then the equilibrium remains stationary. So, tripling (P) while reducing (q) to one third will not alter the equilibrium.

6 0

2 months ago

Suppose a 20.0 g gold bar at 35.0°C absorbs 70.0 calories of heat energy. Given that the specific heat of gold is 0.0310 cal/g °

VMariaS [2998]

The change in temperature can be expressed as:

$T_2-T_1=\dfrac{q}{mC_p(Gold)}$

By substituting in the known values, we arrive at:

$T_2-T_1=\dfrac{70\ cal}{20\ g\times 0.0310\ cal/g^o\ C}\\\\T_2-T_1=112.90^oC\\\\T_2-35^oC=112.90^oC\\\\T_2=(112.90+35)^oC\\\\T_2=147.9^oC$

Thus, we obtain the required answer.

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2 months ago

In which of these statements are protons, electrons, and neutrons correctly compared?

Alekssandra [3086]

<span>Quarks exist inside protons and neutrons but are not components of electrons. Quarks are subatomic particles that possess mass and fractional (non-integer) electric charge. Protons and neutrons are composed of quarks, whereas electrons are not, since electrons are considered energy carriers with charge rather than massive matter. Because quarks have mass, they cannot be part of electrons.</span>

5 0

2 months ago

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What is the molar mass of 81.50g of gas exerting a pressure of 1.75atm on the walls of a 4.92L container at 307K?

Alekssandra [3086]

M = 81.50g, mm = m/n
n =???
PV = nRT --> n = PV/RT
n = (1.75)(4.92)/(.0821)(307)
n = 8.61/25.20 =.342
--> mm = m/n = 81.5/.342 = 238.58

7 0

1 month ago

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Compute 4.659×104−2.14×104. Round the answer appropriately.

lions [2927]

Answer: 25,200.

Explanation:

1) Starting with: 4.659 × 10⁴ - 2.14 × 10⁴

2) Significant figures need to be considered.

Because the powers are equal (10⁴), the decimal values can be subtracted directly. However, it is essential to first check significant figures and the count of decimal places.

3) The figure 4.659 × 10⁴ has four significant digits (4, 6, 5, and 9), whereas 2.14 × 10⁴ contains three significant digits (2, 1, and 4).

4) When adding or subtracting values with a different number of decimal places, the answer must reflect the same number of decimal places as the number with the least amount of decimal precision.

5) Prior to performing subtraction, it is necessary to round the numbers to the least decimal places. Given that 2.14 has two decimal places and 4.659 has three, round 4.659 to 4.66.

6) Now perform the subtraction 4.66 - 2.14 = 2.52

7) Then multiply by the power of 10: 2.52 × 10⁴ = 25,200. This is the final answer.

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1 month ago

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