The vertex of the graph for the function g(x) = (x- 3)^2 + 9 is located 3 units to the right and 9 units upwards compared to the vertex of the function f(x) = x^2.
To find the hypotenuse of a right triangle with sides measuring 3 and 4, we first need to use the Pythagorean theorem and then add that distance to 3 and 4.
By applying the theorem, the square of the hypotenuse equals the sum of the squares of the sides...
d^2=3^2+4^2
d^2=9+16
d^2=25
d=√25
d=5
Thus, the total distance for her run is 5+4+3=12 km
Response:

Step-by-step explanation:

To calculate 5% of our number, we start by multiplying by 0.05

Next, by adding and subtracting this 5% from our original number, we can find the minimum and maximum possible values of our final answer in the specified range.

We can ascertain that
fits within the acceptable range, as:

Therefore, our final answer will be:

Response:
To accumulate $7,500 in three years, the required one-time deposit is $4388.17
Step-by-step explanation:
Basic Financial Formulas
A commonly used formula for calculating present and future values is

Where FV represents the future value, PV denotes the present value, r signifies the interest rate, and n indicates the number of compounding periods. It’s essential to remember that r and n must correspond to the same compounding duration, e.g. r is compounded monthly while n is expressed in months.
The inquiry seeks to determine the PV necessary as a one-time deposit to achieve a future value of $7,500 in 3 years at an interest rate of 1.5% compounded monthly.
FV=7,500
r=1.5%=0.015
n=3*12=36 months
We have changed n to months since r is monthly compounded. The equation

must be arranged to isolate PV.



Response
: The amount necessary as a one-time deposit to accrue $7,500 in three years is $4388.17[[TAG_54]]
Utilize the details to create inequalities that reflect each limitation or requirement.
2) Label the
variables.
c: count of color copies
b: count of black-and-white copies
3)
Define each constraint:
i) <span>Printing a color copy requires 3 minutes while a black-and-white copy takes 1 minute.
</span><span>
</span><span>
3c + b</span><span>
</span><span>
</span><span>ii) He must print
a minimum of 6 copies ⇒
c + b ≥ 6</span><span>
</span><span>
</span><span>iv) Moreover, he must finish the prints within
12 minutes at most ⇒</span>
3c + b ≤ 12<span />
4) Additional limits include
c ≥ 0, and
b ≥ 0 (meaning
only non-negative counts are valid for each type of copy)
5) Here’s how to
illustrate that:
i) For 3c + b ≤ 12: draw the line representing 3c + b = 12 and shade the area above and to the right of this line.
ii) For c + b ≥ 6: draw the line c + b = 6 and shade the area below and to the left of this line.
iii) Given that c ≥ 0 and b ≥ 0, the relevant region is located in the
first quadrant.
iv) The concluding area is the
overlap of the previously mentioned shaded regions.v) The graph can be viewed in the attached figure.