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6 days ago

How do you write 125.06 million dollars in at least four different ways.

Mathematics

2 answers:

Svet_ta [12.3K]6 days ago

7 0

Answer:

Given: 125.06 million dollars

Goal: Provide at least four different representations.

Solution:

It can be shown as,

125.06 million dollars = $125,060,000

In words:

$125,060,000 = One-hundred twenty-five million, and sixty thousand dollars

As a fraction:

$125.06=\frac{12506}{100}=\frac{6253}{50}$

In standard numeric form:

$125.06 \text{million} = 12506\times10^{4}$

Zina [12K]6 days ago

5 0

$125,060,000

one-hundred twenty-five million, and sixty thousand dollars

Also, 125.06 expressed as a fraction is 6253/50, if that representation is acceptable.

You can refer to it as 125.06 million dollars when using the figure from the prompt.

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$0.60 bottle of iced tea marked up to $1.35

zzz [11930]

The result is 0.81 because you must multiply 0.60 by 1.35 to get 0.81. Then divide 0.81 by 0.60.

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1 month ago

Read 2 more answers

An experiment was conducted to record the jumping distances of paper frogs made from construction paper. Based on the sample, th

tester [11989]

Answer:

$9.9676 - 2.326*0.5904 =8.594$

$9.9676 + 2.326*0.5904 =11.341$

Step-by-step explanation:

Notation

$\bar X$ is the sample mean

$\mu$ indicates the population mean (the variable of interest)

s signifies the sample standard deviation

n denotes the sample size

Solution to the problem

The mean's confidence interval is derived from the following formula:

$\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}$ (1)

In this instance, the 9% confidence interval corresponds to:

$8.8104 \leq \mu \leq 11.1248$

We can determine the mean using the following:

$\bar X = \frac{8.8104 +11.1248}{2}= 9.9676$

Additionally, the margin of error can be calculated as:

$ME= \frac{11.1248- 8.8104}{2}= 1.1572$

The margin of error for this situation is expressed as:

$ME = t_{\alpha/2}\frac{s}{\sqrt{n}} = t_{\alpha/2} SE$

Next, we find the standard error:

$SE = \frac{ME}{t_{\alpha/2}}$

The critical value for a 95% confidence interval using a normal standard distribution is roughly 1.96, and substituting gives us:

$SE = \frac{1.1572}{1.96}= 0.5904$

For the 98% confidence interval, the significance corresponds to $\alpha=1-0.98= 0.02$ and $\alpha/2 = 0.01$ with a critical value of 2.326, yielding a confidence interval of:

$9.9676 - 2.326*0.5904 =8.594$

$9.9676 + 2.326*0.5904 =11.341$

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29 days ago

Clarissa's income puts her in the bottom tax bracket (10%) last year. During the same year, she earned $250 in dividends and $75

Leona [12226]

Answer:

75 dollars in coupons.

250 dollars in dividends.

She achieved a profit of 600 - 425 = 175 from her stock investment.

Her complete income sums up to 250 + 75 + 175 = 500.

If all this is taxed at 10%, her tax will be 500 *.1 = 50.

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13 days ago

76% is between which of the following two numbers?

AnnZ [12009]

Hi there!

While there are no answer choices provided, here's how you can solve a problem like this.

To find the average of two numbers, you simply sum them up and divide by two!

For instance, to find the midpoint between 1 and 3, you add 1 and 3 to get 4, then divide by 2 which results in 2!

For 100 and 580, adding gives you 680, and dividing by 2 results in 340!

The average between 0.57 and 0.69 involves adding to get 1.26, then dividing by 2 yields 0.63!

Now, with percentages, for 45% and 67%, the addition gives you 112%, and dividing that by 2 will result in 56%!

So, for your answer options, just calculate the total and divide by two to determine which one results in 76%!

I hope this information helps!

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1 month ago

A journalist wants to determine the average annual salary of CEOs in the S&P 1,500. He does not have time to survey all 1,50

Inessa [12248]

Answer:

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A journalist intends to find the average annual salary of CEOs within the S&P 1,500. Due to time constraints, a sample is used.

Standard deviation of the sample (s) = 449300

Sample size = n

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Z critical value = 1.96

Thus, 1.96 times the standard error equals 50000.

Standard error equals 25510.20

Standard deviation divided by the square root of n = 25510.20

By simplifying, we can derive:

$\sqrt{n} =\frac{449300}{25510.20} =17.752\\n=315\\$

Thus, the minimum sample size required is 315.

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1 month ago