7.35 moles of oxygen. Initially, for each mole of H₂CO₃, there are 3 moles of oxygen, as derived from the acid's formula. For 2.45 moles of the compound stated in the problem, which is carbonic acid, we calculate: If 1 mole of H₂CO₃ corresponds to 3 moles of oxygen, then for 2.45 moles of H₂CO₃, we have X moles of oxygen. Thus, X = (3 × 2.45) / 1 = 7.35 moles of oxygen.
Answer:
The specific gravity of the saturated solution is 2
Explanation:
Specific gravity represents the ratio of the density of a solution, in this case, a saturated potassium iodide (KI) solution, to the density of water. Assuming the density of water is 1:
Specific gravity = Density
Density itself is defined as the mass divided by volume.
In 100mL of water, the mass of dissolve-able KI is:
100mL * (1g KI / 0.7mL) = 143g of KI
This indicates that all 100g of KI dissolves (Mass solute)
With 100mL of water corresponding to a mass of 100g (Mass solvent)
The overall mass of the solution computes to 100g + 100g = 200g
In a volume of 100mL, the solution's density is:
200g / 100mL = 2g/mL.
Specific gravity is a dimensionless quantity, thus the specific gravity of the saturated solution is 2
Response:
K = 6.5 × 10⁻⁶
Detailed Explanation:
C₅H₆O₃ ⇄ C₂H₆ + 3CO
Apply PV=nRT to determine the initial pressure of C₅H₆O₃
P (2.50) = (0.0493) (0.08206) (473)
P = 0.78atm
C₅H₆O₃ ⇄ C₂H₆ + 3CO
0.78atm 0 0
0.78 - x x 3x
1.63atm = 0.78 - x + x + 3x
P(total) = 0.288atm
C₅H₆O₃ = 0.78 - 0.288
= 0.489atm
C₂H₆ = 0.288atm
CO = 0.846atm
= 0.379
= 6.5 × 10⁻⁶
