A saturated solution of potassium iodide contains, in each 100 mL, 100 g of potassium iodide. The solubility of potassium iodide

Step 1: Convert density from g/mL to g/L; 0.807 g/mL is equivalent to 807 g/L. Step 2: Calculate Moles of N₂; Density = Mass / Volume, or Mass = Density × Volume. Plugging in values, Mass = 807 g/L × 1 L gives us Mass = 807 g. Similarly, Moles = Mass / M.mass, which leads to Moles = 807 g / 28 g.mol⁻¹, giving us Moles = 28.82 moles. Step 3: Apply the Ideal Gas Law to determine Volume of gas occupied; P V = n R T, thus V = n R T / P. Remember to convert temperature to Kelvin (25 °C + 273 = 298 K). Hence, V = (28.82 mol × 0.08206 atm.L.mol⁻¹.K⁻¹ × 298 K) ÷ 1 atm, resulting in V = 704.76 L.

Answer: Copper is being oxidized and acts as a reducing agent. In contrast, silver is being reduced, functioning as the oxidizing agent.

Explanation:

An oxidation reaction involves the loss of electrons by an atom. Here, the oxidation state of the atom rises.

Conversely, a reduction reaction is characterized by an atom gaining electrons, resulting in a decrease in its oxidation state.

Oxidizing agents are those that facilitate the oxidation of another substance while themselves being reduced. These substances participate in reduction reactions.

Reducing agentsare defined as those that reduce other substances while undergoing oxidation themselves. They also take part in reduction reactions.

In the provided chemical reaction:

The associated half-reactions for the above process are:

Oxidation half reaction:  

Reduction half reaction:  

From the reactions outlined, copper is losing electrons. Consequently, it is oxidized and regarded as a reducing agent.

Silver is acquiring electrons, thus it is being reduced and viewed as an oxidizing agent.

Answer:

are present in solution.

Explanation:

Molarity of the solution = 0.210 M

Volume of the solution = 65.5 ml = 0.0655 L

Moles of aluminum iodide = n

n = 0.013755 moles of aluminum iodide

Each mole of aluminum iodide yields 3 moles of iodide ions:

Thus, 0.013755 moles of aluminum iodide will provide:

moles of iodide ions

The total number of iodide ions in 0.041265 moles:

are present in solution.

Answer:

8 protons, 8 electrons, and 10 neutrons

Explanation:

Answer: The apparent density of ethylene glycol 3350 is calculated as 3350 = 17g/15.6mL= 1.09g/mL

The specific gravity of the mixture is 1.01

Explanation:

Specific gravity refers to the density of a substance compared to that of a reference substance, typically water.

Specific gravity = density of substance/density of water

The density of a substance measures the mass of that substance relative to its volume.

Density = Mass/Volume

The density of water is known to be 1.00 g/mL,  

Apparent density of ethylene glycol 3350 is assessed as mass/volume

the volume of ethylene glycol = total volume of mixture - volume occupied by water

volume of ethylene glycol = 195.6 - 180 = 15.6 mL

Apparent density of ethylene glycol 3350 = 17g/15.6mL= 1.09g/mL

mass of water is computed as  density of water multiplied by volume of water

mass of water = 1.00g/mL * 180mL = 180 g

Total mass of solution = mass of substance plus mass of water = (17 + 180)g = 197g

Density of the mixture = total mass of the mixture divided by its volume

Density of mixture = 197 g / 195.6 mL = 1.01 g/mL

To find the specific gravity of the mixture, use the formula:

specific gravity of mixture = density of mixture divided by density of water

specific gravity of mixture = 1.01g/mL / 1.00g/mL

specific gravity of mixture = 1.01