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Bas_tet
12 days ago
15

(a) calculate %ic of the interatomic bonds for the intermetallic compound al6mn. (b) on the basis of this result what type of in

teratomic bonding would you expect to be found in al6mn?
Chemistry
1 answer:
KiRa [971]12 days ago
6 0

The answer is:

a) 0.25%

b) metallic bond

Explanation:

This can be determined through the following formula to quantify the percentage of ionic character of a compound with some covalent traits: percentage of ionic character = Observed dipole moment divided by Calculated dipole moment assuming 100% ionic nature times 100.

- The percentage of ionic character relies on the electronegativities of elements XA and XB. In this case, the electronegativities of Al and Mn are 1.5 and 1.6, respectively.

For the calculation: %IC = [1 - exp(-1/4) (XB-XA)^2] × 100

This results in %IC = [1 - exp(-0.25)(1.6 - 1.5)^2] × 100 = 0.25%

(b) Because the ionic character is so minimal (0.25%) and since the compound is made of two metals, Al and Mn, the bonding is entirely metallic.

Metallic bond details:

- It can vary in strength, being either weak (68 kJ/mole or 0.7 eV/atom for Hg) or strong (850 kJ/mole or 8.8 eV/atom for W).

- Metallic bonds enable high levels of electrical and thermal conductivity.

- The electrons, being loosely bound as each atom has multiple vacant valence orbitals, can move freely, allowing atoms to slide past one another easily.

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Which of the following could be considered a scientific statement?
Anarel [852]

Answer: D) X-rays exhibit lower frequency than microwaves

Explanation:

A scientific statement is one that relies on evidence gathered from experiments and direct observation of the natural world. Such a statement can be corroborated through appropriate experimental methods.

The option D illustrates a scientific statement because it allows for the frequency of both microwaves and X-rays to be assessed and contrasted. This process entails experimental and observational techniques, which validates it as a scientific statement.

6 0
2 days ago
Read 2 more answers
A 0.784 g sample of magnesium is added to a 250 ml flask and dissolved in 150 ml of water. magnesium hydroxide obtained from the
Anarel [852]

Although multiple values are given, our focus is on HCl.

<span>We have 215 mL (0.215 L) of 0.300 M HCl fully consumed in the reaction. It's important to recall that the number of moles is found by multiplying volume by molarity:</span>

 

moles = 0.215 L × 0.300 M

<span>moles = 0.0645 moles of HCl</span>

4 0
15 days ago
Consider butter (density= 0.860 g/mL) and sand (density= 2.28 g/mL). If 1.00 mL of butter were mixed with 1.00 mL of sand and mi
Anarel [852]

The mixture’s density is 1.57 g/cm³.


Step 1: Determine the mass of the butter.


\text{Mass} = \text{1.00 cm}^{3 } \times \frac{\text{0.680 g} }{\text{1 cm}^{3 }} = \text{0.860 g}\\

Step 2: Determine the mass of the sand.


\text{Mass} = \text{1.00 cm}^{3 } \times \frac{\text{2.28 g} }{\text{1 cm}^{3 }} = \text{2.28 g}\\

Step 3: Determine the density of the mixture.

Total mass = 0.860 g + 2.28 g = 3.14 g.

Total volume = 1 cm³ + 1 cm³ = 2 cm³

\text{Density} = \frac{\text{mass}}{\text{volume}} = \frac{\text{3.14 g} }{\text{2 cm}^{3 }} = \textbf{1.57 g/cm}{^{3}\\

6 0
1 day ago
Which of the following reactions is a redox reaction? (a) K2CrO4 + BaCl2 → BaCrO4 + 2KCl (b) Pb2+ + 2Br- → PbBr2 (c) Cu + S → Cu
castortr0y [923]

(c) Cu + S → CuS is classified as a redox reaction

Explanation:

The following reactions are presented:

(a) K₂CrO₄ + BaCl₂ → BaCrO₄ + 2 KCl

(b) Pb²⁺ + 2 Br⁻ → PbBr₂

(c) Cu + S → CuS

Reaction (c) represents a redox reaction, as the oxidation states of the elements are changing. In this case:

Cu + S → CuS

In its elemental form, Cu has an oxidation state of 0, while in CuS (copper sulfide), its oxidation state changes to +2.

Similarly, S in its elemental form has an oxidation state of 0 and is -2 in CuS (copper sulfide).

Learn more about:

redox reactions

7 0
1 day ago
In living organisms, C-14 atoms disintegrate at a rate of 15.3 atoms per minute per gram of carbon. A charcoal sample from an ar
lions [985]

Answer:

The result is "4,241.17 years"

Explanation:

The disintegration rate for C-14 atoms is indicated in  15.3 \frac{atoms}{min-g}

The dissolution rate of the sample is given by 9.16 \frac{atoms} {min-gram}

The C-14 proportion within the sample can be determined as per = \frac {9.16}{15.3} \\\\ = 0.5987

With a half-life of 5730 years.

Now, we need to compute the number of half-lives (n) that are applicable:

(\frac{1}{2})^n= A\\\\A= fraction of C-14, which is remaining \\\\(\frac{1}{2})^n= 0.5987 \\\\ n \log 2 = - \log 0.5987\\\\

\therefore \\\\ \Rightarrow n= \frac{0.227}{0.3010} \\\\ = 0.740\\

Thus, the age of the sample is represented as = n \times\ half-life

                                                 = 0.740 \times 5730 \ years \\\\=4241.17 \ years\\\\

6 0
1 day ago
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