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Bas_tet
1 month ago
15

(a) calculate %ic of the interatomic bonds for the intermetallic compound al6mn. (b) on the basis of this result what type of in

teratomic bonding would you expect to be found in al6mn?
Chemistry
1 answer:
KiRa [2.9K]1 month ago
6 0

The answer is:

a) 0.25%

b) metallic bond

Explanation:

This can be determined through the following formula to quantify the percentage of ionic character of a compound with some covalent traits: percentage of ionic character = Observed dipole moment divided by Calculated dipole moment assuming 100% ionic nature times 100.

- The percentage of ionic character relies on the electronegativities of elements XA and XB. In this case, the electronegativities of Al and Mn are 1.5 and 1.6, respectively.

For the calculation: %IC = [1 - exp(-1/4) (XB-XA)^2] × 100

This results in %IC = [1 - exp(-0.25)(1.6 - 1.5)^2] × 100 = 0.25%

(b) Because the ionic character is so minimal (0.25%) and since the compound is made of two metals, Al and Mn, the bonding is entirely metallic.

Metallic bond details:

- It can vary in strength, being either weak (68 kJ/mole or 0.7 eV/atom for Hg) or strong (850 kJ/mole or 8.8 eV/atom for W).

- Metallic bonds enable high levels of electrical and thermal conductivity.

- The electrons, being loosely bound as each atom has multiple vacant valence orbitals, can move freely, allowing atoms to slide past one another easily.

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A student mixed 20.00 grams of calcium nitrate, 10.00 grams of sodium nitrate, and 50.00 grams of aluminum nitrate in a 5.00 Lit
lorasvet [2795]

Response:

For each nitrate-based salt, we assess the nitrate mole count, as depicted below:M=0.213M

n_{NO_3^-}=20.00gCa(NO_3)_2*\frac{1molCa(NO_3)_2}{164.088 gCa(NO_3)_2} *\frac{2molNO_3^-}{1molCa(NO_3)_2} =0.244molNO_3^-

n_{NO_3^-}=10.00gNaNO_3*\frac{1molNaNO_3}{84.9947 gNaNO_3} *\frac{1molNO_3^-}{1molNaNO_3} =0.118molNO_3^-

n_{NO_3^-}=50.00gAl(NO_3)_3*\frac{1molAl(NO_3)_3}{212.996gAl(NO_3)_3} *\frac{3molNO_3^-}{1molAl(NO_3)_3} =0.704molNO_3^-

Calcium nitrate contributes two moles of nitrate, sodium nitrate provides one, and aluminum nitrate contains three. Summing the moles gives us the total nitrate mole count:

n_{NO_3^-}^{Tot}=0.244+0.118+0.704=1.066molNO_3^-

Ultimately, we proceed to calculate the molarity:

M=\frac{1.066molNO_3^-}{5.00L} \\\\M=0.213M

Best,

6 0
27 days ago
34.62 mL of 0.1510 M NaOH was needed to neutralize 50.0 mL of an H2SO4 solution. What is the concentration of the original sulfu
Anarel [2989]

0.1045M represents the concentration of the initial sulfuric acid solution

Explanation:

Titration is conducted to ascertain the volume or concentration of an unknown electrolyte.

Given data:

acid volume = 50 ml

acid molarity =?

NaOH volume = 34.62 ml

molarity of NaOH = 0.1510

The titration formula applied is

Macid x Vacid = Mbase x Vbase

Substituting the values into the above equation results in:

Macid x 50 = 34.62 x 0.1510

Macid = \frac{5.22762}{50}

           = 0.1045 M, indicating the molarity of the sulfuric acid solution used to neutralize the 0.1510 M base solution.

5 0
28 days ago
Suppose you need of Grade 70 tow chain, which has a diameter of and weighs , to tow a car. How would you calculate the mass of t
VMariaS [2998]

Answer: refer to the explanation

Explanation:

This question requires calculating mass. To determine the mass, we need values for two parameters, namely the specifications for the grade 70 tow chain and the mass per unit length given.

Assuming the mass per unit length is 3 kilograms per meter (kg/m) and the length of the grade 70 tow chain is 5 meters (m).

Thus, the formula used to compute the mass of the chain is as follows;

Mass of the chain = mass per unit length (kg/m) × length ---------------------------------------------------------------------------------------------------------------------(1).

Mass of the chain = 3 kg/m × 5 m.

Mass of the chain equals 15 kg.

7 0
1 month ago
The graph above shows the changes in temperature recorded for the 2.00 l of h2o surrounding a constant-volume container in which
Alekssandra [3086]

Answer:

25.2 kJ

Explanation:

The full question can be found in the image linked to this response.

It's important to highlight that the heat absorbed by the 2.00 L of water for increasing its temperature from the beginning to the end comes solely from the burning of benzoic acid, as there are no heat transfers to the container or the surroundings.

To find the heat released from benzoic acid combustion, we simply measure the heat needed to warm the water.

Q = mCΔT

To find the mass of the water,

Density = (mass)/(volume)

Mass = Density × volume

Density = 1 g/mL

Volume = 2.00 L = 2000 mL

Mass = 1 × 2000 = 2000 g

C = specific heat of water = 4.2 J/g.°C

ΔT = (final temperature) - (Initial temperature)

<pAccording to the graph,

Final water temperature = 25°C

Initial water temperature = 22°C

ΔT = 25 - 22 = 3°C

Q = (2000×4.2×3) = 25,200 J = 25.2 kJ

Hope this Helps!!!

6 0
1 month ago
A student described two properties of a substance shown below which of the following is true about the two properties described
eduard [2782]

Answer:

B

Explanation:

Flammable substances contain chemicals that react with flames, thus making it their chemical property, particularly when they encounter other materials that cause a reaction.

7 0
17 days ago
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