Answer:
The heat capacity of the calorimeter is
= 54.4 
Explanation:
Given the data
Heat supplied Q = 4.168 KJ = 4168 J
Mass of water
= 75.40 gm
Change in temperature = ΔT = 35.82 - 24.58 = 11.24 °C
From the conditions provided
Q =
ΔT +
ΔT
Plugging all values into the above equation yields
4168 = 75.70 × 4.18 × 11.24 +
× 11.24
611.37 =
× 11.24
= 54.4 
This represents the heat capacity of the calorimeter.
Clarification:
To obtain the specific element, you should multiply the grams provided by the ratio of grams of that particular element within its complete compound.
Since the query did not indicate the amount of NO2 produced, we can consider its mass to be negligible, thus assigning 1 mole to Nitrogen.
The question appears to be confusing. The periodic table consists of elements organized by increasing atomic number.
Answer:
The temperature of a vessel at a pressure reading of 1.250 atm is 296.43 K.
Explanation:
At standard temperature and pressure (STP), the temperature is valued at 273.15 K with a pressure of 1.000 atm.
If the pressure is measured as 1.250 atm at temperature T.


Applying Gay Lussac's law:
(When volume is constant)


At a pressure of 1.250 atm, the temperature of the vessel is 296.43 K.
The reaction that exhibits the lowest K value is:
A + B → 2 C; E°cell = -0.030 V.
This can be rationalized by noting that the standard electrode potential of the cell is directly proportional to the reaction's equilibrium constant. A higher potential results in a larger K value, whereas a lower potential yields a smaller K value.