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Umnica
12 days ago
10

Two bulbs are connected by a stopcock. The large bulb, with a volume of 6.00 L, contains nitric oxide at a pressure of 0.700 atm

, 0.700 atm, and the small bulb, with a volume of 1.50 L, contains oxygen at a pressure of 2.50 atm. The temperature at the beginning and the end of the experiment is 22 ∘ C 22∘C . After the stopcock is opened, the gases mix and react. 2 NO ( g ) + O 2 ( g ) → 2 NO 2 ( g ) 2NO(g)+O2(g)→2NO2(g)
Which gases are present at the end of the experiment?
Chemistry
1 answer:
VMariaS [2.7K]12 days ago
3 0
At constant temperature, the amount of gas in a system is proportional to the product of its pressure and volume. Thus, nitric oxide and oxygen gas quantities are represented respectively by their pressure and volume.
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Response:

This is my understanding.

Explanation:

(g) Titration curves

While I can't create two curves on a single graph, I can depict them separately for clarity.

In part (d), the graph indicated an equivalence point at 20 mL.

For the second titration, since the NaOH concentration is doubled, the volume to reach the equivalence point will be halved — 10 mL.

Below are the two titration curves.

(h) Evidence of reaction

Both HCl and NaOH are colorless solutions.

There is no gas released or precipitate formed during their reaction.

It’s likely the student observed that the Erlenmeyer flask heated up, indicating a chemical change.

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If practical applications for chemistry hadn't been explored, our understanding of what it means to be human, and the biological aspects that make us who we are, would remain unclear. Moreover, we wouldn't have achieved significant advancements in areas such as vaccines and other critical fields.

Explanation:

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castortr0y [2808]

Answer:

Cuando dos átomos se acercan entre sí, se genera un compuesto al compartir pares de electrones que cada uno de los átomos aporta, permitiéndoles alcanzar los 8 electrones de valencia (octeto) en su capa externa.

Explanation:

La configuración electrónica del elemento puede escribirse de la siguiente manera;

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La configuración electrónica dada es equivalente a la del oxígeno, por lo tanto, tenemos;

El número de electrones en la capa de valencia = 2 + 4 = 6 electrones

Por consiguiente, cada átomo necesita 2 electrones para completar sus 8 electrones (octeto) en la capa externa.

Al acercarse los dos átomos, reaccionan y se combinan para formar un compuesto al compartir 4 electrones, 2 de cada átomo, de modo que cada átomo obtenga 2 electrones adicionales en su órbita externa en el nuevo compuesto y así se logre la configuración estable de octeto para cada uno de los átomos en el compuesto recién formado.

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Answer:

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