Ethylene glycol is known as the main component found in antifreeze.
The molecular formula for ethylene glycol is C₂H₆O₂.
Its molar mass is calculated as C₂H₆O₂ = (2×12) +(6×1) + (216) = 62g/mol
Given that antifreeze comprises 50% by weight, there exists 1 kg of ethylene glycol mixed with 1 kg of water.
ΔTf = Kf×m
ΔTf refers to the change in the freezing point.
= starting temperature of water - freezing temperature of the solution
= 0°C - Tf
= -Tf
Kf stands for the freezing point depression constant of water, which is 1.86°C/m
m is the molarity of the solution.
=(mass/molar mass) where mass of solvent is in kg
=1000g/62 (g/mol) /1kg
=16.13m
Substituting the value into the equation gives us
-Tf = 1.86 × 16.13 = 30
thus Tf = -30°C
Newton's First Law: A body remains in its current state of motion or at rest unless a force acts upon it.
Newton's Second Law: Motion changes are proportional to the applied force and oriented in the same direction.
Newton's Third Law: Every action has a corresponding and opposite reaction.
Tasks that would be challenging to perform in orbit include:
-operating a valve
-navigating on foot
-attempting to take a shower
-remaining still
It is 8 kilograms. I had to provide more text, so here it is.
<span>A centripetal force maintains an object's circular motion. When the ball is at the highest point, we can assume that the ball's speed v is such that the weight of the ball matches the required centripetal force to keep it moving in a circle. Hence, the string will not become slack.
centripetal force = weight of the ball
m v^2 / r = m g
v^2 / r = g
v^2 = g r
v = sqrt { g r }
v = sqrt { (9.80~m/s^2) (0.7 m) }
v = 2.62 m/s
Thus, the minimum speed for the ball at the top position is 2.62 m/s.</span>
Response:

Clarification:
If
-
,
represent the temperatures of gases and liquids in Kelvins,
and
denote the thicknesses of the gas layer and steel slab in meters,
,
are the convection coefficients for gas and liquid in
,
represents the contact resistance in
,
- and
signify thermal conductivities of gas and steel in
,
then: part(a):

by employing known values:
part(b): Utilizing the rate equation:
the surface temperature is 
and 
Correspondingly


The temperature profile is depicted in the image provided