The nardo ring is a circular test track for cars. it has a circumference of 12.5 km. cars travel around the track at a constant

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The nardo ring is a circular test track for cars. it has a circumference of 12.5 km. cars travel around the track at a constant

speed of 100 km/h. a car starts at the easternmost point of the ring and drives for 7.5 minutes at this speed. what is the magnitude of the car's displacement, in km, from its initial position?

Physics

2 answers:

Sav [3.1K] · Answer 1 · 2026-03-13T23:37:04+03:00

The car's displacement is measured at 0 m.

For further clarity

Acceleration refers to the change of velocity over time.

$\large {\boxed {a = \frac{v - u}{t} } }$

$\large {\boxed {d = \frac{v + u}{2}~t } }$

a = acceleration (m / s²)v = final velocity (m / s)

u = initial velocity (m / s)

t = time taken (s)

d = distance (m)

Let's move forward to solve the problem!

Details given:

Circumference = C = 12.5 km

Speed = v = 100 km/h

Time = t = 7.5 minutes, which equals 0.125 h

Unknown variable:

Displacement = d =?

Now, let’s determine the distance the car has traveled.

$Distance = Speed \times Time$

$Distance = 100 ~ km/h \times 0.125 ~ h$ Given that the track's circumference corresponds to the distance the car travels, it effectively returns to its original position.Thus, the car's displacement computes to 0 m.

For more insights

Runner's Velocity:

Kinetic Energy:

Acceleration:

Car's Speed:

Answer details

Grade: High School

Subject: Physics

Chapter: Kinematics

Keywords: Velocity, Driver, Car, Deceleration, Acceleration, Obstacle, Speed, Time, Rate

ValentinkaMS [3.4K] · Answer 2 · 2026-03-13T23:35:39+03:00

In the realm of physical science, quantities are categorized into two types: scalar and vector quantities. Scalar quantities only possess magnitude, whereas vector quantities encompass both magnitude and direction. Displacement pertains to the measurement from the initial position to the final position of an object. The formula to compute the distance covered by an object is given by D = s x t, where D represents distance, s denotes speed, and t indicates time. Remember to adjust units appropriately to ensure that those in the numerator and denominator cancel out in the fraction form. Applying this, we find D = (100 km/h)(7.5 min)(1 h/60 min) = 12.5 km. This suggests that the object returned to its starting point, therefore, the displacement equals ZERO.