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ankoles
4 months ago
6

Approximately 1.000 g each of four gasses H2, Ne, Ar, and Kr are placed in a sealed container all under1.5 atm of pressure. Assu

ming ideal behavior, determine the partial pressure of the H2 and Ne
Physics
1 answer:
serg [3.5K]4 months ago
7 0

Answer:

The partial pressure of H2 is 0.375 atm.

The partial pressure of Ne also stands at 0.375 atm.

Explanation:

Mass of H2 = 1 g

Mass of Ne = 1 g

Mass of Ar = 1 g

Mass of Kr = 1 g

Overall mass of the gas mixture totals 4 g.

Pressure in the sealed container is 1.5 atm.

Calculating the partial pressure for H2 yields: (mass of H2/total mass of gas mixture) × pressure of sealed container = 1/4 × 1.5 = 0.375 atm.

Calculating the partial pressure for Ne similarly gives: (mass of Ne/total mass of gas mixture) × pressure of sealed container = 1/4 × 1.5 = 0.375 atm.

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