Response: The spring constant is 25 N/m.
Details:
The body’s mass is 25 g, which converts to 0.025 kg (since 1 kg = 1000 g).
The total oscillations are 20 in 4 seconds.
Oscillations per second =
Spring's frequency of vibration is =
The spring constant 'k' can be derived from the relationship involving frequency, mass, and spring constant.
The spring constant is 25 N/m.
Answer:
a = 18.28 ft/s²
Explanation:
the values provided are:
duration of force application, t= 10 s
Work done = 10 Btu
mass of the object = 15 lb
acceleration, a =? ft/s²
1 Btu = 778.15 ft.lbf
thus, 10 Btu = 7781.5 ft.lbf
m = 0.466 slug
So,
the work is equivalent to the change in kinetic energy
The acceleration of the object is therefore
a = 18.28 ft/s²
the constant acceleration of the object is calculated to be 18.28 ft/s²
Broad questions addressed by conducting this experiment involve the effects of electric current.
Electric current measures the quantity of electric charge passing per unit time.
It results from electrons moving due to a voltage difference (high potential to low potential) between two points.
These electrons flow through wires acting as conductors.
Ohm's Law states that:
The potential difference across a conductor is proportional to the current flowing through it, assuming resistance remains the same.
A basic electrical circuit consists of a voltage source (battery) and a lamp.
Ammeters used to measure current must be connected in series with the load.
By adjusting the voltage while resistance is constant, varying current values are observed; increasing voltage produces higher current.
Electron flow inside devices
Keywords: basic electric circuits, Ohm's law, experiment