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mihalych1998
1 month ago
7

Which combination of initial horizontal velocity, (vh) and initial vertical velocity, (vv) results in the greatest horizontal ra

nge for a projectile over level ground? [neglect friction.] 1. 2. 3. 4?
Physics
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A book rests on the shelf of a bookcase. The reaction force to the force of gravity acting on the book is 1. The force of the sh
serg [3582]

Answer:

1. The force applied by the shelf supporting the book.

Explanation:

The free body diagram for the book is represented as follows:

1 - The weight of the book acting downward

2 - The normal force exerted by the shelf upward on the book.

As the book remains stationary, these two forces balance each other, and in accordance with Newton's Third Law, the reactive force equivalent to gravity is opposite and equal to the weight of the book. This reaction force prevents the book from falling off the shelf.

6 0
3 months ago
Read 2 more answers
In the demolition of an old building, a 1,300 kg wrecking ball hits the building at 1.07 m/s2. Calculate the amount of force at
Ostrovityanka [3204]
The force can be determined using the equation F (force) = mass * acceleration. The unit of measurement, N (Newton), is equivalent to kilogram-meter/seconds2.
Thus, F= 1300 kg * 1.07 m/s2 = 1391 N.
The resultant value is 1391 N.
7 0
2 months ago
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A 50-kg load is suspended from a steel wire of diameter 1.0 mm and length 11.2 m. By what distance will the wire stretch? Young'
Ostrovityanka [3204]

Answer:

3.5 cm

Explanation:

mass, m = 50 kg

diameter = 1 mm

radius, r = half the diameter = 0.5 mm = 0.5 x 10^-3 m

L = 11.2 m

Y = 2 x 10^11 Pa

Cross-sectional area of the wire = π r² = 3.14 x 0.5 x 10^-3 x 0.5 x 10^-3

= 7.85 x 10^-7 m^2

Let the change in length of the wire be ΔL.

The equation for Young's modulus is given by

Y =\frac{mgL}{A\Delta L}

\Delta L =\frac{mgL}{A\times Y}

ΔL = 0.035 m = 3.5 cm

Thus, the wire stretches by 3.5 cm.

5 0
4 months ago
In the Netherlands, there is an annual ice-skating race called the "Tour of the Eleven Towns." The total distar.rce of the cours
Keith_Richards [3271]

Answer:

a) La velocidad promedio del récord de la carrera es de 35.2 km/h

b) El tiempo que tomará cubrir la primera mitad es 2h 42 min.

Explicación:

a) Para calcular la velocidad promedio del récord, se divide la distancia total por el tiempo:

v = distancia / tiempo

Ahora, expresaremos el tiempo en horas:

si 60 s es 1 min, entonces 37 s será (37 s · 1 min/60 s) 0.62 min.

Si 60 min es 1 h, entonces 40.62 min será (40.62 min · 1 h/60 min) 0.68 h.

Por lo tanto, el tiempo récord es 5.68 h.

La velocidad promedio será:

v = 2.00 × 10² km / 5.68 h = 35.2 km/h

b) Ahora que tenemos la velocidad y la distancia, podemos determinar el tiempo que le tomará al patinador cubrir esa distancia:

La velocidad será:

v = 1.05v = 1.05 · 35.2 km/h = 37.0 km/h

La distancia será:

2.00 × 10² km / 2 = 1.00 × 10² km

Luego:

v = distancia / tiempo

tiempo = distancia / v = 1.00 × 10² km / 37.0 km/h = 2.70 h

Si 1 h son 60 min, 0.70 h será (0.70 h · 60 min/h) 42 min.

Entonces, el tiempo necesario para cubrir la primera mitad es de 2h 42 min.

3 0
4 months ago
When water freezes, it expands about nine percent. What would be the pressure increase inside your automobile engine block if th
Keith_Richards [3271]

Answer:

The increase in pressure within the engine block of the car amounts to 1782.18 ATM.

Explanation:

Provided:

the volume change of water, ΔV = 9%

the bulk modulus for ice, K = 2 x 10⁹ N/m²

It is calculated using the bulk modulus formula;

K = -V\frac{dP}{dV}

so when the water freezes, the pressure increase in the automobile engine block is;

dP = K(\frac{dV}{V} )\\\\dP = K(\frac{0.09V}{V} )\\\\dP = 0.09K\\\\dP = 0.09 (2*10^9)\\\\dP = 1.8 *10^{8} \ N/m^2\\\\dP = 1782.18 \ ATM

Thus, the final pressure increase inside the automobile engine block is 1782.18 ATM.

6 0
4 months ago
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