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Verdich
4 months ago
5

In the Netherlands, there is an annual ice-skating race called the "Tour of the Eleven Towns." The total distar.rce of the cours

e is 2.00 x 102 krn, and the record time for covering it is 5 h,40 min, 37 s. a. Calculate the average speed of the record race. b. If the first half of the distance is covered by a skater moving with a speed o[ 1.05v, where y is the average speed found in (a), how long will it take to skate the first halft Express your answer in hours and minutes.
Physics
1 answer:
Keith_Richards [3.2K]4 months ago
3 0

Answer:

a) La velocidad promedio del récord de la carrera es de 35.2 km/h

b) El tiempo que tomará cubrir la primera mitad es 2h 42 min.

Explicación:

a) Para calcular la velocidad promedio del récord, se divide la distancia total por el tiempo:

v = distancia / tiempo

Ahora, expresaremos el tiempo en horas:

si 60 s es 1 min, entonces 37 s será (37 s · 1 min/60 s) 0.62 min.

Si 60 min es 1 h, entonces 40.62 min será (40.62 min · 1 h/60 min) 0.68 h.

Por lo tanto, el tiempo récord es 5.68 h.

La velocidad promedio será:

v = 2.00 × 10² km / 5.68 h = 35.2 km/h

b) Ahora que tenemos la velocidad y la distancia, podemos determinar el tiempo que le tomará al patinador cubrir esa distancia:

La velocidad será:

v = 1.05v = 1.05 · 35.2 km/h = 37.0 km/h

La distancia será:

2.00 × 10² km / 2 = 1.00 × 10² km

Luego:

v = distancia / tiempo

tiempo = distancia / v = 1.00 × 10² km / 37.0 km/h = 2.70 h

Si 1 h son 60 min, 0.70 h será (0.70 h · 60 min/h) 42 min.

Entonces, el tiempo necesario para cubrir la primera mitad es de 2h 42 min.

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