Answer:
15.71g
Explanation:
The combustion equation that applies to hydrocarbons is
CxHy + (x+y/4) O2 = xCO2 + (y/2) H2O
In the case of octane, C8H18:
C8H18 + ( 8 + 18/4 ) O2 = 8CO2 + 9H2O
C8H18 + 50/4 O2 = 8CO2 + 9H2O
C8H18 + 25/2 O2 = 8CO2 + 9H2O
2C8H18 + 25 O2 = 16 CO2 + 18H2O (this is the balanced equation)
From this balanced reaction,
2 x 22.4 L of octane generates 16 [ 12 + (16 x 2)] of carbon dioxide
That means,
44.8 L of octane generates 704g of carbon dioxide
Thus, for 1L of octane, it produces 1 L x 704g/44.8 L = 15.71g of carbon dioxide
Consequently, 15.71g of carbon dioxide is produced from the complete combustion of 1 L of octane.
Answer:
The dependent variable in this experiment is the egg's position above the water.
Explanation:
The dependent variable refers to the factor that is influenced by another variable.
On the other hand, the independent variable is what can be altered, affecting the dependent variable's outcome.
The controlled variable remains constant throughout the experiment.
In this setup, the amount of salt added acts as the independent variable, while the flotation level of the egg is the dependent variable, and the water volume in each cup represents the controlled variable.
1. The total moles of the solution is 0.3079193 mol.
2. The mole fraction for gold is 0.2473212, and for silver, it is 0.7526787.
3. The molar entropy of mixing for gold is 2.87285 j/K, while for silver, it is 1.77804 j/K.
4. The total entropy of mixing sums to 4.65089 j/K.
5. Molar free energy amounts to -2325.445 kJ.
6. Chemical potential for silver is -1750.31129 j/mol and for gold, it is -575.13185 j/mol. To elaborate:
(1) The molar mass of silver stands at 107.8682 g/mol, and gold's at 196.96657 g/mol. Hence, calculating moles leads to mass/molar mass for silver: 25 g/107.8682 g/mol = 0.2317643 mol and for gold: 15 g/196.96657 g/mol = 0.076155 mol, resulting in a total of 0.30791193 mol.
(2) For the mole fractions, silver's fraction is 0.2317643/0.3079193 = 0.7526787, and for gold, it's 0.076155/0.3079193 = 0.2473212.
(3) To find molar entropy mixing ∆Sm, we use the formula ∆Sm = -R * Xi * ln(Xi) where R = 8.3144598. For silver, substituting gives us 1.77804 j/K, while for gold, we get 2.87285 j/K.
(4) Overall entropy of mixing totals 4.65089 j/K thus calculated.
(5) The Gibbs free energy at 500 °C can be derived through G = H - TS, accounting to H = 0 (as T is 500 + 273 = 773 K and S is 4.65089), resulting in G equating to -3595.138 kJ.
(6) The chemical potentials calculated derive from multiplying the Gibbs free energy by their mole fractions.
The concentration of the HCl solution can be determined as follows:
The reaction equation is written as
NaOH + HCl = NaCl + H2O
Next, the moles of NaOH are calculated: moles = molarity x volume /1000
= 5 x 2/1000 = 0.01 moles
Using the mole ratio of NaOH to HCl, which is 1:1, the moles of HCl is also equal to 0.01 moles
The concentration is given by: concentration = moles/volume x 1000
= 0.01/10 x 1000 = 1M
