An atom that contains four electrons in its valence shell is capable of forming multiple types of bonds: single bonds, as an atom fitting this description can create four single bonds or a mix of single, double, and triple bonds. Take for instance alkanes, where this atom could form one double bond along with two single bonds, or conversely, two double bonds, which is seen in alkenes. For triple bonds, this atom could make one triple bond and a single bond, as seen in alkynes.
Answer:
The ratios arranged in ascending order are; The ratio of the mass of Y to X in XY2 divided by the mass of Y to X in XY, The ratio of the mass of Y to X in XY3 divided by the mass of Y to X in XY, The ratio of the mass of Y to X in XY4 divided by the mass of Y to X in XY
1) Mass ratio = 3
2) Mass ratio = 2
3) Mass ratio = 4
Explanation:
Comprehensive calculations are displayed in the attachment.
<span>128 g/mol
Applying Graham's law of effusion, we can utilize the formula:
r1/r2 = sqrt(m2/m1)
where
r1 = effusion rate of gas 1
r2 = effusion rate of gas 2
m1 = molar mass of gas 1
m2 = molar mass of gas 2
Given that the atomic weight of oxygen is 15.999, the molar mass of O2 = 2 * 15.999 = 31.998.
We can now insert the known values into Graham's equation to find m2.
r1/r2 = sqrt(m2/m1)
2/1 = sqrt(m2/31.998)
4/1 = m2/31.998
Thus, we find m2 to be 127.992.
Rounding to three significant figures yields 128 g/mol</span>
What is being removed during the wash is the solvent.
