The principle of conservation of mass asserts that mass cannot be created or eliminated. Given that element A has a mass of 2 g/mol and element B has a mass of 3 g/mol, the total mass of compound AB equals the combined molar masses: 2 g/mol + 3 g/mol results in 5 g/mol for AB. As for A2B3, the calculation is as follows: A2 has 2 multiplied by 2, yielding 4 g/mol, while B3 equals 3 multiplied by 3, which gives 9 g/mol. Consequently, A2B3 amounts to 13 g/mol.
Answer:
Cuando dos átomos se acercan entre sí, se genera un compuesto al compartir pares de electrones que cada uno de los átomos aporta, permitiéndoles alcanzar los 8 electrones de valencia (octeto) en su capa externa.
Explanation:
La configuración electrónica del elemento puede escribirse de la siguiente manera;
1s²2s²2p⁴
La configuración electrónica dada es equivalente a la del oxígeno, por lo tanto, tenemos;
El número de electrones en la capa de valencia = 2 + 4 = 6 electrones
Por consiguiente, cada átomo necesita 2 electrones para completar sus 8 electrones (octeto) en la capa externa.
Al acercarse los dos átomos, reaccionan y se combinan para formar un compuesto al compartir 4 electrones, 2 de cada átomo, de modo que cada átomo obtenga 2 electrones adicionales en su órbita externa en el nuevo compuesto y así se logre la configuración estable de octeto para cada uno de los átomos en el compuesto recién formado.
Answer:
The right answer is "1.0100".
Explanation:
Assuming the total volume of the mixture is 100 ml.
Thus,
The volume of DMSO will be 10 mL and the volume of water will be 90 mL.
For DMSO:
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= 
The total mass of the mixture will be:
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= 
Calculating the density of the mixture:
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= 
= 
Thus,
The specific gravity of the mixture is:
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The concentration of the drug stock solution measures 1.5 × 10^-9 M, indicating that there are 1.5 × 10^-9 moles of the drug for every liter of solution.
To determine the number of moles in 1 ml (which is 1 × 10^-3 L), calculate: 1 × 10^-3 L × 1.5 × 10^-9 moles/1 L = 1.5 × 10^-12 moles.
Each mole of the drug consists of 6.023 × 10^23 molecules.
Thus, for 1.5 × 10^-12 moles of the drug, the corresponding number of molecules is:
1.5 × 10^-12 moles × 6.023 × 10^23 molecules/1 mole = 9.035 × 10^11 molecules.
The total number of cancer cells is 2.0 × 10^5.
The ratio hence equals the drug molecules divided by the cancer cells:
9.035 × 10^11 / 2.0 × 10^5 = 4.5 × 10^6.
A flood that affects the environment where natural rubber is produced would severely hinder rubber production. In order to greatly limit production, a flood would need to destroy a significant portion of rubber trees. Natural rubber is crucial for manufacturing synthetic polymers. If the rubber supply is compromised (due to the disruption of its ecosystem caused by a flood), there would be a substantial decline in the availability of synthetic polymers.
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